R的新手并寻求一些帮助。如何从R中的以下xml转换为数据框。数据框应包含3列各列id。
<?xml version="1.0" encoding="UTF-8" ?>
- <results version="1" total-rows="3" current-page="1" current-page-start-row="1" current-page-end-row="25" execution-time="0.0781255">
- <columns>
<column id="ReferenceNumber" data-type="ReferenceNumber">Reference Number</column>
<column id="AllocatedTo" data-type="Allocation">Allocated To</column>
<column id="Reason" data-type="Category">Category Code</column>
</columns>
- <rows>
- <row case-reference="0150967018">
<data column-id="ReferenceNumber">0150967018</data>
<data column-id="AllocatedTo">Suresh</data>
<data column-id="Reason">Actioned incorrectly</data>
</row>
- <row case-reference="0150967118">
<data column-id="ReferenceNumber">0150967118</data>
<data column-id="AllocatedTo">Suresh</data>
<data column-id="Reason">Actioned incorrectly</data>
</row>
- <row case-reference="0150967218">
<data column-id="ReferenceNumber">0150967218</data>
<data column-id="AllocatedTo">Suresh</data>
<data column-id="Reason">Actioned incorrectly</data>
</row>
</rows>
</results>
答案 0 :(得分：0)
希望这有帮助！
library(xml2)
library(dplyr)
#pass your xml string to xml_text
xml_doc <- read_xml(xml_text)
df <- xml_doc %>%
xml_find_all("//rows/row/data") %>%
xml_text %>%
matrix(ncol=3, byrow=T) %>%
as.data.frame(stringsAsFactors=FALSE)
colnames(df) <- xml_doc %>%
xml_find_all("//columns/column") %>%
xml_text
df
输出是：
Reference Number Allocated To Category Code
1 0150967018 Suresh Actioned incorrectly
2 0150967118 Suresh Actioned incorrectly
3 0150967218 Suresh Actioned incorrectly
答案 1 :(得分：0)
XML到数据框为了有效处理大文件中的数据，我们将xml文件中的数据作为数据框读取。然后处理数据 数据分析框架。
# Load the packages required to read XML files.
library("XML")
library("methods")
# Convert the input xml file to a data frame.
xmldataframe <- xmlToDataFrame("input.xml")
print(xmldataframe)
当我们执行上面的代码时，它会产生以下结果-
Reference Number Allocated To Reason
1 0150967018 Suresh Actioned incorrectly
2 0150967118 Suresh Actioned incorrectly
3 0150967218 Suresh Actioned incorrectly
由于现在可以将数据用作数据框，因此我们可以使用与数据框相关的功能来读取和操作文件。