从json到CollectionView Custom单元swift4的图像数组

时间:2018-02-27 19:43:03

标签: ios swift uicollectionview

我想将数据从我的JSON Url传递到我的集合视图单元格,所以在解析了我的json之后我有了一些URL链接,问题是如何将它发送到单元格imageView?

这是我的代码

import UIKit

class ItemsListViewController: UIViewController, UICollectionViewDelegate, UICollectionViewDataSource{

  var myItems = [Item]()


  func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
    return myItems.count
  }

  func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "CollectionViewCell", for: indexPath) as! CollectionViewCell

    cell.itemPriseLabel.text = myItems[indexPath.row].currentPrice

    let imageUrl =   myItems[indexPath.row].productImageUrl
    print(imageUrl)


    cell.itemImage.image? = imageUrl[indexPath.row]

    return cell
  }

  var category1: Categories?

  @IBOutlet weak var colectionViewVariable: UICollectionView!

  override func viewDidLoad() {
    super.viewDidLoad()
    downloadJSON3 {
        self.colectionViewVariable.reloadData()

    }

    colectionViewVariable?.dataSource = self
    colectionViewVariable?.delegate = self

    // Do any additional setup after loading the view.
  }

}

2 个答案:

答案 0 :(得分:0)

foreach ($results as $each_results) { 
    while (list($key, $value) = each ($each_results)) { 
        $id = mysqli_real_escape_string($connection, $results[data][$key][id]); ...
  

重复:找到答案HERE我已将其堆叠成一个简明的答案,但您一定应该阅读链接中的答案,因为它更完整,更完美。

答案 1 :(得分:0)

func collectionView(_ collectionView:UICollectionView,cellForItemAt indexPath:IndexPath) - > UICollectionViewCell {         让cell = collectionView.dequeueReusableCell(withReuseIdentifier:“CollectionViewCell”,for:indexPath)为! CollectionViewCell

    cell.itemPriseLabel.text = myItems[indexPath.row].currentPrice

    if let imageUrl = myItems[indexPath.row].productImageUrl.first {

        URLSession.shared.dataTask(with: imageUrl, completionHandler: { (data, response, error) in
            guard let data = data, response != nil, error == nil else {return}


            DispatchQueue.main.async(execute: { () -> Void in
                let image = UIImage(data: data)

                if let cell = collectionView.cellForItem(at: indexPath) as? CollectionViewCell {
                    cell.itemImage.image = image
                }

            })
        }).resume()

    }

    return cell
}