Question

我希望EasyMock模拟能够多次预期空列表，即使第一次返回的列表中添加了元素。

这可能吗？由于在期望中创建的空列表仍然存在于整个重播中，因此保留在调用之间添加到其中的任何元素。

这是一个代码示例，显示了我要避免的内容：

public class FakeTest {

private interface Blah {

    public List<String> getStuff();
};

@Test
public void theTest(){

    Blah blah = EasyMock.createMock(Blah.class);

    //Whenever you call getStuff() an empty list should be returned
    EasyMock.expect(blah.getStuff()).andReturn(new ArrayList<String>()).anyTimes();

    EasyMock.replay(blah);

    //should be an empty list
    List<String> returnedList = blah.getStuff();
    System.out.println(returnedList);

    //add something to the list
    returnedList.add("SomeString");
    System.out.println(returnedList);

    //reinitialise the list with what we hope is an empty list
    returnedList = blah.getStuff();

    //it still contains the added element
    System.out.println(returnedList);

    EasyMock.verify(blah);
}
}

Answer 1

您可以使用andStubReturn每次生成一个新列表。

//Whenever you call getStuff() an empty list should be returned
EasyMock.expect(blah.getStuff()).andStubAnswer(new IAnswer<List<String>>() {
        @Override
        public List<Object> answer() throws Throwable {
            return new ArrayList<String>();
        }
    }

如何让EasyMock模拟多次返回空列表

1 个答案: