我正在将数组转换为要打印的字符串，但编译器仍然说不可迭代。
Traceback (most recent call last):
File "python", line 157, in <module>
File "python", line 56, in total
TypeError: 'int' object is not iterable
函数total()位于第56行，如果您认为这是问题，但是如果您运行该脚本，您会发现该函数在每个其他实例中都能正常工作。
import random
import time
def makeDeck():
cards = []
num = 1
for card in range(52):
cards.append(num)
num += 1
if num == 13:
num = 1
return cards
#def shuffle(cards):
#for card in cards:
#num = random.randint(0,51)
#cards.insert(0, cards[num])
#return cards
def shuffle(deck):
for card in deck:
hold = deck.pop(0)
deck.insert(random.randint(1,51),hold)
return deck
def cardToString(hand):
cardString = []
for card in hand:
if card == 1:
cardString.append('Ace')
elif card == 11:
cardString.append('Jack')
elif card == 12:
cardString.append('Queen')
elif card == 13:
cardString.append('King')
else:
cardString.append(str(card))
for card in cardString:
return card
def deal(user,deck):
hand = []
for x in range(2):
hand.append(deck.pop(0))
return hand
def deal1(user,deck):
hand = []
for card in deck:
hand.append(deck.pop(0))
return hand
def total(hand):
score = 0
for card in hand:
if(card>10):
score += 10
elif(card != 1):
score += card
else:
if(score>=11):
score+=1
else:
score+=11
return score
#def playGame():
#to do
name1 = input('Player 1, please enter your name:\n')
p2q = input('Will there be two plaers? (y/n)')
if(p2q == 'y' or p2q == 'Y' ):
p2yn = 1
name2 = input('Player 2, please enter your name:\n')
elif(p2q == 'n' or p2q == 'N'):
p2yn = 0
deck = makeDeck()
shuffle(deck)
p1hand = deal(name1,deck)
if(p2yn == 1):
p2hand = deal(name2,deck)
else:
print(end = ' ')
hs=0
print(str(name1)+', your hand is:', end = ' ' )
cardToString(p1hand)
print(str(p1hand[0])+',',p1hand[1], end = ' ')
print('and your total is', total(p1hand))
time.sleep(2)
tot1 = total(p1hand)
while(tot1 < 21):
p1cvar = input('Would you like another card? (y/n)\n')
if(p1cvar =='n' or p1cvar == 'N'):
break
else:
p1hand.append(deck.pop(0))
newCard = str(p1hand[-1])
cardToString(newCard)
print('You got a', newCard)
time.sleep(1)
print('Your total is now', total(p1hand))
time.sleep(1)
if(total(p1hand) <= 21):
hs = total(p1hand)
else:
print('You went over 21!')
p1hand=0
time.sleep(1)
break
if(p1hand != 0):
print('The high score is', total(p1hand), 'held by', str(name1)+'.')
time.sleep(1)
shuffle(deck)
if(p2yn == 1):
print(str(name2)+', your hand is:', end = ' ' )
cardToString(p2hand)
print(str(p2hand[0])+',',p2hand[1], end = ' ')
print('and your total is', total(p2hand))
time.sleep(2)
tot1 = total(p2hand)
while(tot1 < 21):
p2cvar = input('Would you like another card? (y/n)\n')
if(p2cvar =='n' or p2cvar == 'N'):
break
else:
p2hand.append(deck.pop(0))
newCard = str(p2hand[-1])
cardToString(newCard)
print('You got a', newCard)
time.sleep(1)
print('Your total is now', total(p2hand))
time.sleep(1)
if(total(p2hand)>21):
print('You went over 21!')
p2hand=0
time.sleep(1)
break
if(p2hand != 0 and total(p2hand)>hs):
print('The high score is', total(p2hand), 'held by', str(name2)+'.')
hs = total(p2hand)
time.sleep(1)
dealerHand = deal('Dealer',deck)
print("The dealer's hand is:", end = ' ' )
cardToString(dealerHand)
print(str(dealerHand[0])+',',dealerHand[1], end = ' ')
print('and their total is', total(dealerHand))
time.sleep(2)
totD = total(dealerHand)
while(totD < 21):
tdh = total(dealerHand)
if(tdh<hs and tdh<22):
dealerHand.append(deck.pop(0))
newCard = str(dealerHand[-1])
cardToString(newCard)
print('Dealer got a', newCard)
time.sleep(.5)
print("Dealer's total is now", total(dealerHand))
time.sleep(1)
if(total(dealerHand) <= 21 and total(dealerHand)>hs):
hs = total(dealerHand)
else:
print('Dealer went over 21!')
dealerHand=0
else:
break
if(dealerHand != 0):
print('The high score is', total(dealerHand), 'held by', str("Dealer")+'.')
while(total(p1hand)>21 or total(dealerHand)>21):
if(total(dealerHand)>21):
print('Dealer has been eliminated from play!')
elif(total(p1hand)>21):
print(name1,'has been eliminated from play!')
答案 0 :(得分：1)
从代码块底部开始大约11行，您将经销商的手设置为0：
....
else:
print('Dealer went over 21!')
dealerHand=0
这是令人担忧的，因为他们的手应该是一个清单。因此，当您尝试迭代它以计算总数时，您会得到一个int不可迭代。
应该是
之类的东西dealerHand = []
此外，在此之后的几行，当你认为是dealerHand!=0
total(dealerHand)是否#Around line 111
print('You went over 21!')
p1hand=0
time.sleep(1)
break
.....
#Around line 140
print('You went over 21!')
p2hand=0
time.sleep(1)
break
您还应该小心将其中的变量从列表更改为int的其他分配，例如
<f:SimpleForm id="phoneFormSimple" editable="true" layout="ResponsiveGridLayout" title="Phone Numbers" columnsM="1" columnsL="1">
<f:content>
<core:Title text="Business Phone"/>
<Label text="Number" design="Bold">
<layoutData>
<l:GridData span="XL2 L2 M2 S6"/>
</layoutData>
</Label>
<MaskInput id="businessPhoneNumber" value="{business_phone_number}" placeholder="Enter number..." mask="(CCC) CCC-CCCC"
placeholderSymbol="_">
<rules>
<MaskInputRule maskFormatSymbol="C" regex="[0-9]"/>
</rules>
<layoutData>
<l:GridData span="XL4 L4 M4 S6"/>
</layoutData>
</MaskInput>
<Label text="Extension" design="Bold">
<layoutData>
<l:GridData span="XL2 L2 M2 S6"/>
</layoutData>
</Label>
<Input id="businessPhoneExtension" value="{business_phone_extension}">
<layoutData>
<l:GridData span="XL4 L4 M4 S6"/>
</layoutData>
</Input>
<core:Title text="Business Fax"/>
<Label text="Number" design="Bold">
<layoutData>
<l:GridData span="XL2 L2 M2 S6"/>
</layoutData>
</Label>
<MaskInput id="buinessFaxNumber" value="{business_fax_number}" placeholder="Enter number..." mask="(CCC) CCC-CCCC" placeholderSymbol="_">
<rules>
<MaskInputRule maskFormatSymbol="C" regex="[0-9]"/>
</rules>
<layoutData>
<l:GridData span="XL4 L4 M4 S6"/>
</layoutData>
</MaskInput>
</f:content>
</f:SimpleForm>
因为Python不是强类型，改变给定变量名的类型会导致很多这类问题
答案 1 :(得分：0)
R：170,6：经销商的重新定义从列表到int的类型 （重新定义的可变型）
这将在未来帮助您。