如何从单个客户端TCP c＃多次接收数据

Question

我正在尝试监听客户端多次发送数据。我不知道如何在客户端第二次发送数据时让服务器监听客户端。现在我可以多次通过客户端发送数据，但服务器只接受客户端数据一次。请帮忙。

客户端

//the client
    private TcpClient client = new TcpClient();

    //constructor
    public ClientConnect(string Ip, int Port)
    {
        IP = Ip;
        PORT = Port;
    }
    //write the data to the server
    public void Connect(byte[] clientId)
    {
        //try to connect to the server
        Thread t = new Thread(() =>
        {
            while (true)
            {
                try
                {
                    client.Connect(new IPEndPoint(IPAddress.Parse(IP), PORT));
                    break;
                }
                catch (SocketException)
                {
                    Console.Clear();
                    Console.WriteLine("Trying to connect to the server...");
                    //pass if the connection failed
                }
            }
            client.GetStream().Write(clientId, 0, (int)clientId.Length);
        });
        t.Start();
    }
    public void SendData(byte[] data)
    {
        Thread t2 = new Thread(() => {
            while (true)
            {
                try
                {
                    client.GetStream().Write(data, 0, (int)data.Length);
                    break;
                }
                catch (System.InvalidOperationException)
                {
                    //pass
                }
            }
        });
        t2.Start();
    }

服务器：

while (true)
            {
                //Listen for a potential client
                TcpClient client = tcpServer.AcceptTcpClient();
                Console.WriteLine(client);

                Console.WriteLine("Client connection accepted from " + client.Client.RemoteEndPoint + ".");

                byte[] buffer = new byte[client.ReceiveBufferSize];
                int bytesRead = client.GetStream().Read(buffer, 0, (int)buffer.Length);
                byte[] buffer2 = new ArraySegment<byte>(buffer, 0, bytesRead).ToArray();

                //do something with the data 
            }