Question

我需要为下面的查询转换数据，当前数据在3列中.Case1，case2 check image1 current result 我需要Month作为每个月下的column和case1，case2数据。检查图像2 expected result

select 

month(pe.contact_date) as Month, 
sum (case when pt.sex_c=1 and pe.ENC_TYPE_C = '3'  then 1 else 0  end) as case1,
sum (case when pt.sex_c=1 and pe.ENC_TYPE_C = '101'  then 1 else 0  end) as case2

from
patient pt, pat_enc pe
where
pt.PAT_ID=pe.PAT_ID

group by month (pe.CONTACT_DATE)
order by month (pe.CONTACT_DATE)

Answer 1

您要做的事情似乎是“转置”操作。这是一种可能有用的通用方法，因为我不知道你是否有'pivot / unpivot'操作。

select
    case when month(pe.CONTACT_DATE) % 2 =  1 then 'case1' else 'case2' end) as "??"
    min(case when month(pe.CONTACT_DATE) =  1 then case1 else case2 end) as "1"
    min(case when month(pe.CONTACT_DATE) =  2 then case1 else case2 end) as "2"
    ...
    min(case when month(pe.CONTACT_DATE) = 12 then case1 else case2 end) as "12"
from <table> pe
group by month(pe.CONTACT_DATE) % 2

Answer 2

这应该按照您需要的方式转动数据

select      case when pt.sex_c=1 and pe.ENC_TYPE_C = '3'  then 'case1' 
                 when pt.sex_c=1 and pe.ENC_TYPE_C = '101' then 'case2' 
            end as casetype,
            count(case when month(pe.contact_date) = 1 then 1 end) as [1],
            count(case when month(pe.contact_date) = 2 then 1 end) as [2],
            count(case when month(pe.contact_date) = 3 then 1 end) as [3],
            count(case when month(pe.contact_date) = 4 then 1 end) as [4],
            count(case when month(pe.contact_date) = 5 then 1 end) as [5],
            count(case when month(pe.contact_date) = 6 then 1 end) as [6],
            count(case when month(pe.contact_date) = 7 then 1 end) as [7],
            count(case when month(pe.contact_date) = 8 then 1 end) as [8],
            count(case when month(pe.contact_date) = 9 then 1 end) as [9],
            count(case when month(pe.contact_date) = 10 then 1 end) as [10],
            count(case when month(pe.contact_date) = 11 then 1 end) as [11],
            count(case when month(pe.contact_date) = 12 then 1 end) as [12]
from        patient pt
join        pat_enc pe on pt.pat_id = pe.pat_id
group by    case when pt.sex_c=1 and pe.ENC_TYPE_C = '3'  then 'case1' when pt.sex_c=1 and pe.ENC_TYPE_C = '101' then 'case2' end

SQL - 在一个透视上透视多个列

2 个答案: