Question

我有一个python元组，其元素实际上是句子。我想比较每个元素的第一个字母，如果它们是小写的，我将它连接到前一个元素。如果他们不是我加入第一个元素。例如，如果我有：

tuple1 = ('Traditionally, companies have been communicating', 'with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence', 'which is incomplete.')

我的结果应该是：

tuple1 = ('Traditionally, companies have been communicating with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence which is incomplete.')

这是我的工作代码：

i=0 
while i<(len(tuple1)-1):
   if tuple1[i+1][0].islower():
       tuple1[i] + " " + tuple[i+1]
   i+=1

我怎样才能做到这一点？感谢

Answer 1

您可以使用itertools.groupby：

import itertools  
tuple1 = ('Traditionally, companies have been communicating', 'with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence', 'which is incomplete.')
new_data = tuple(' '.join(i[-1] for i in b) for _, b in itertools.groupby(enumerate(tuple1), key=lambda x:x[-1][0].islower() or tuple1[x[0]+1][0].islower() if x[0]+1 < len(tuple1) else True))

输出：

('Traditionally, companies have been communicating with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence which is incomplete.')

Answer 2

希望这能满足您的需求。我没有使用任何外部模块就做到了。

look_these_up

Answer 3

正如第一条评论所述，元组是不可变的。使用列表可能更容易，如果你真的需要一个元组，你可以在之后将结果列表转换为一个。

return

应该照顾它。您需要最后一行来清除temp_list。

比较和连接Python中的元组

3 个答案: