我正在尝试解析jmeter soap响应(XML),但是我得到了一个解析错误
org.xml.sax.SAXParseException: Content is not allowed in prolog
我已经使用在线工具验证了SOAP响应(XML)是有效的,但无济于事。我仍然得到一个错误。即使我试图获得一个漂亮的XML输出,我也会得到null错误,因为解析导致了null。
代码段如下:
import groovy.util.XmlSlurper;
import groovy.util.XmlParser;
import groovy.util.slurpersupport.NodeChild;
def xmlContent = ctx.getPreviousResult().getResponseDataAsString();
log.info(xmlContent);
def stringWriter = new StringWriter()
def parse = new XmlSlurper();
def respParse = parse.parseText(xmlContent);
log.info(respParse);
def test = new XmlNodePrinter(new PrintWriter(stringWriter)).print(respParse)
log.info(test);
XML是:
<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<ns2:Response xmlns:ns2="URL" xmlns="URL" xmlns:ns4="URL" xmlns:ns3="URL" xmlns:ns5="URL">
<something>Code</something>
<somethingDescription>Message</somethingDescription>
<ns2:pending/>
<ns2:posted/>
</ns2:Response>
</soapenv:Body>
</soapenv:Envelope>
关于我做错了什么的想法
答案 0 :(得分:1)
你的错误变量与行中的值:
def respParse = parse.parseText("xmlContent");
您已传递字符串而不是变量xmlContent
。它应该是:
def respParse = parse.parseText(xmlContent);
答案 1 :(得分:0)
我设法使用以下代码解决了这个问题:
import groovy.util.XmlSlurper;
def xmlContent = ctx.getPreviousResult().getResponseDataAsString();
log.info(xmlContent);
def resp = new XmlSlurper().parseText(xmlContent);
def result = resp.Body.Response;
def respCode = resp.Body.Response.ResponseCode;
def respCodeDesc = resp.Body.Response.Description;
log.info(respCode.toString());