＆＃34;＆＃34;中的奇怪行为大熊猫时间戳的熊猫列功能

Question

你刚刚注意到＆＃34;＆＃34;的一些奇怪的行为。 pandas数据框的功能。

我在feedTable pandas数据表中有两列日期，索引和名为＆＃39; date_forecast_adjusted＆＃39;的列。我需要改变一些日期，具体取决于日期是否已经在两列中。似乎我可以很容易地检查转移的日期是否在索引中，但是对于列，＆＃34; in＆＃34;命令似乎不起作用。

我尝试了以下命令：

(datePD + i*timedelta(hours=24))
Timestamp('2015-12-28 00:00:00')

pd.to_datetime("28/12/2015",dayfirst=True)
Timestamp('2015-12-28 00:00:00')

feedTable[feedTable['date_forecast_adjusted']==
pd.to_datetime("28/12/2015",dayfirst=True)]['date_forecast_adjusted'][0]
Timestamp('2015-12-28 00:00:00')

feedTable[feedTable['date_forecast_adjusted']==(datePD + 
i*timedelta(hours=24))]['date_forecast_adjusted'][0]
Timestamp('2015-12-28 00:00:00')

feedTable[feedTable['date_forecast_adjusted']==
pd.to_datetime("28/12/2015",dayfirst=True)]['date_forecast_adjusted'][0]==
(datePD + i*timedelta(hours=24))
True

(datePD + i*timedelta(hours=24)) in feedTable['date_forecast_adjusted']
False

pd.to_datetime("28/12/2015",dayfirst=True) in 
feedTable['date_forecast_adjusted']
False

pd.to_datetime("28/12/2015",dayfirst=True) in 
feedTable[feedTable['date_forecast_adjusted']==
pd.to_datetime("28/12/2015",dayfirst=True)]['date_forecast_adjusted']
False

pd.Series((datePD + 
i*timedelta(hours=24))).isin(feedTable['date_forecast_adjusted'])
0    True

any(feedTable['date_forecast_adjusted'] ==
(datePD + i*timedelta(hours=24)) )
True

我会说in in function ...