Question

我有2个表名为EmployeeInfo和Leave，我存储了员工已经采取了哪些类型的假期和次数的值。我试图计算相同类型的叶子的数量，但我长时间停留在一个点上。

IF EXISTS(SELECT 1 FROM sys.tables WHERE object_id = OBJECT_ID('Leave'))
BEGIN;
    DROP TABLE [Leave];
END;
GO

IF EXISTS(SELECT 1 FROM sys.tables WHERE object_id = OBJECT_ID('EmployeeInfo'))
BEGIN;
    DROP TABLE [EmployeeInfo];
END;
GO

CREATE TABLE [EmployeeInfo] (
[EmpID] INT NOT NULL PRIMARY KEY,
[EmployeeName] VARCHAR(255)
);

CREATE TABLE [Leave] (
    [LeaveID] INT NOT NULL PRIMARY KEY,
    [LeaveType] VARCHAR(255) NULL,
    [DateFrom] VARCHAR(255),
    [DateTo] VARCHAR(255),
    [Approved] Binary,
    [EmpID] INT FOREIGN KEY REFERENCES EmployeeInfo(EmpID)
);
GO


INSERT INTO EmployeeInfo([EmpID], [EmployeeName]) VALUES
(1, 'Marcia'),
(2, 'Lacey'),
(3, 'Fay'),
(4, 'Mohammad'),
(5, 'Mike')


INSERT INTO Leave([LeaveID],[LeaveType],[DateFrom],[DateTo], [Approved], [EmpID]) VALUES
(1, 'Annual Leave','2018-01-08 04:52:03','2018-01-10 20:30:53', 1, 1),
(2, 'Sick Leave','2018-02-10 03:34:41','2018-02-14 04:52:14', 0, 2),
(3, 'Casual Leave','2018-01-04 11:06:18','2018-01-05 04:11:00', 1, 3),
(4, 'Annual Leave','2018-01-17 17:09:34','2018-01-21 14:30:44', 0, 4),
(5, 'Casual Leave','2018-01-09 23:31:16','2018-01-12 15:11:17', 1, 3),
(6, 'Annual Leave','2018-02-16 18:01:03','2018-02-19 17:16:04', 1, 2)

我到目前为止尝试的查询看起来像这样。

SELECT Info.EmployeeName, Leave.LeaveType, SUM(DATEDIFF(Day, Leave.DateFrom, Leave.DateTo)) [#OfLeaves], DatePart(MONTH, Leave.DateFrom)

FROM EmployeeInfo Info, Leave

WHERE Info.EmpID = Leave.EmpID AND Approved = 1  

GROUP BY Info.EmployeeName, Leave.LeaveType, [Leave].[DateFrom], [Leave].[DateTo]

以下给出的记录

EmployeeName   LeaveType         #OfLeaves   MonthNumber
-------------- ----------------- ----------- -----------
Fay            Casual Leave      1           1
Fay            Casual Leave      3           1
Lacey          Annual Leave      3           2
Marcia         Annual Leave      2           1

我希望记录看起来像这样

    EmployeeName   LeaveType         #OfLeaves   MonthNumber
    -------------- ----------------- ----------- -----------
    Fay            Casual Leave      4           1
    Lacey          Annual Leave      3           2
    Marcia         Annual Leave      2           1

Answer 1

如果由于某些约束而不想修改现有查询，则可能有效：

Select iq.EmployeeName, iq.LeaveType, SUM(iq.#OfLeaves) as #OfLeaves, iq.MonthNumber 
From (
    SELECT  Info.EmployeeName, Leave.LeaveType, SUM(DATEDIFF(Day, Leave.DateFrom, Leave.DateTo)) [#OfLeaves], DatePart(MONTH, Leave.DateFrom) as MonthNumber
    FROM    EmployeeInfo Info, Leave
    WHERE   Info.EmpID = Leave.EmpID AND Approved = 1  
    GROUP BY Info.EmployeeName, Leave.LeaveType, [Leave].[DateFrom], [Leave].[DateTo]
)iq
group by iq.EmployeeName, iq.LeaveType, iq.MonthNumber

Answer 2

这只需要在GROUP BY子句中对您的查询进行小幅调整。不是按[Leave].[DateFrom]和[Leave].[DateTo]对它们进行分组，而是将行分开，而是需要将其与使用 datepart 的计算列进行分组。

SELECT  Info.EmployeeName, 
        Leave.LeaveType, 
        SUM(DATEDIFF(Day, Leave.DateFrom, Leave.DateTo)) [#OfLeaves], 
        DatePart(MONTH, Leave.DateFrom)
FROM    EmployeeInfo Info
        INNER JOIN Leave
          ON Info.EmpID = Leave.EmpID
WHERE   Approved = 1  
GROUP   BY Info.EmployeeName, 
         Leave.LeaveType, 
         DatePart(MONTH, Leave.DateFrom)  -- <<<< change only this part

这里是Demo。

我还将语法修改为ANSI格式。

一个月内相同类型的叶子总数

2 个答案: