如何将多个函数存储为字典的值？

Question

在下面的代码中，我尝试将多个函数存储为字典的值。这段代码不起作用。这两个函数作为元组返回。但是我不想在词典上喋喋不休。我想使用一个特殊的键，然后我希望字典运行这两个函数。

from functools import partial

def test_1(arg_1 = None):
     print "printing from test_1 func with text:", arg_1

def test_2(arg_2 = None):
     print "printing from test_2 func with text:", arg_2

dic = {'a':(partial(test_1, arg_1 = 'test_1'),
            partial(test_2, arg_2 = 'test_2'))}

dic['a']()

Answer 1

您可以构建一个闭包来执行此操作：

代码：

def chain_funcs(*funcs):
    """return a callable to call multiple functions"""
    def call_funcs(*args, **kwargs):
        for f in funcs:
            f(*args, **kwargs)

    return call_funcs

测试代码：

def test_1(arg_1=None):
    print("printing from test_1 func with text: %s" % arg_1)


def test_2(arg_2=None):
    print("printing from test_2 func with text: %s" % arg_2)


from functools import partial
dic = {'a': chain_funcs(partial(test_1, arg_1='test_1'),
                        partial(test_2, arg_2='test_2'))}

dic['a']()

结果：

printing from test_1 func with text: test_1
printing from test_2 func with text: test_2