Question

所以我有一个石头剪刀游戏。当用户完成他们指定的＃轮次时，系统会提示他们是否要继续，以及他们想要多少轮次。然而，无论我选择什么，循环都会永远持续下去。忽略if语句来结束循环。继承我的代码的while循环部分：

while again == True:

    print("It is ",name,"'s", " turn. What do you pick (R)ock, (P)aper, or (S)cissors?: ", sep = '',end = "")
    print()
    print()
    user = str.lower(input())
    print()

    if user != "s" and user != "r" and user != "p":
        print("Invalid input. Try again.")
        print()
        continue
    else:

        if user == "r":
            userchoice = "rock"

            rock()
            print()

            print(name,"picks Rock!")
        if user == "p":
           userchoice = "paper"

           paper()
           print()
           print(name,"picks Paper!")


        elif user == "s":
            userchoice = "scissors"

            X()
            print()
            print(name,"picks Scissors!")


        print("Now it's computers turn....")
        print('.')
        time.sleep(1)
        print('.')
        time.sleep(1)
        print('.')
        print()

        cpu = random.randint(1,3)
        if cpu == 1:
            cpuchoice = "rock"
            rock()
            print()
            print(" Computer picks rock!")

        if cpu == 2:
            cpuchoice = "paper"
            paper()
            print()
            print("Computer picks paper!")

        elif cpu ==3:
            cpuchoice = "scissors"
            X()
            print()
            print("Computer picks scissors!")


        if cpuchoice == "rock" and userchoice == "scissors" or (cpuchoice == "paper" and userchoice == "rock") or cpuchoice == "scissors" and userchoice == "paper":
            print("Computer wins this round!")
            cscore += 1
        elif cpuchoice == userchoice:
            print("Draw!")
        else:
            print(name,"Wins this round!")
            uscore +=1

        print()
        itt += 1
        print(itt)
        print(rounds)
        print(again)
        print(uscore)
        print(cscore)
        if itt == rounds and uscore == cscore:
            print("It's still a tie! Let's go one more round")
            print()
            itt -= 1
        elif cscore + uscore == rounds:




            if uscore > cscore:
                print(name,"wins!")
            else:
                print("Computer wins!")
            again = input("Play again? Enter 0 to quit.Anything else to continue")
            if again != "0":
                  rounds = input("How many rounds this time?")
                  itt = 0
                  uscore = 0
                  cscore = 0
                  again = True

            else:
                again = False

Answer 1

你再次缩进！= 0＆＃39;块已关闭，我不知道Python在解析空格时使用的确切规则，但它可能是导致问题的原因。

Answer 2

我怀疑您的问题与支票elif cscore + uscore == rounds:有关。如果你打了一个领带并跑了一轮，你的两个分数之后就不会正确加起来。由于您正在检查确切的相等性，因此代码的最后部分将无法运行，游戏也不会结束。

虽然您可以使用>=代替==来解决这个问题，但我认为直接检查itt（应该更好地命名，如round_counter）可能比将分数加在一起更有意义。或者哎呀，你可以像这样重组整个事情：

if itt >= rounds:
    if uscore == cscore:
        # tied, play another round

    else:
        # game over, say who won, ask about playing again

while while循环忽略if语句

2 个答案: