Question

我在底部包含了短代码，然后是错误响应。我试图通过获取输入变量（年龄）并向其添加值2来创建新变量（agep）以获得数值结果。为什么我会收到错误以及打印所需结果的正确方法是什么？

   print ("Welcome")
   myVar = "Hello"
   myName = input ("What is your name?") 
   print (myVar + " " + myName)
   age = input ("What is your age?")
   print ("You are " +age)
   agep = age + 2
   print ("You will be " + agep + " in 730 days")

错误：第8行，在 agep = age + 2 TypeError：必须是str，而不是int

Answer 1

您的age变量正在被读取为字符串。尝试明确地告诉Python在创建agep时将其读作int：

print ("Welcome")
myVar = "Hello"
myName = input ("What is your name?") 
print (myVar + " " + myName)
age = input ("What is your age?")
print ("You are " +age)
# Here, transform age to int so that you can add 2 (another int)
agep = int(age) + 2
# Here, turn it back into a string to be able to concatenate with other strings
print ("You will be " + str(agep) + " in 730 days")

以下是您可能想要查看的python数据类型的一些background reading

Answer 2

因为Python没有对String和Integer值求和：因此，如果要添加年龄，则必须将age变量设置为整数：像这样：int(age)（用2添加age变量。）

最后，要进行打印，您必须再次将integer variable更改为string，如下所示：str(agep)。

，您的代码为：

 print ("Welcome")
 myVar = "Hello"
 myName = input ("What is your name?") 
 print (myVar + " " + myName)
 age = input("What is your age?")
 print ("You are " +age)
 agep = int(age) + 2
 print ("You will be " + str(agep) + " in 730 days")

Python3 - 字符串/整数错误

2 个答案: