我已设置Serilog使用以下命令登录MSSql:
Log.Logger = new LoggerConfiguration()
.MinimumLevel.Debug()
.MinimumLevel.Override("Microsoft", LogEventLevel.Information)
.MinimumLevel.Override("System", LogEventLevel.Information)
.MinimumLevel.Override("Microsoft.AspNetCore.Authentication", LogEventLevel.Information)
.Enrich.FromLogContext()
.WriteTo.Async(x => x.MSSqlServer(logConntectionString, tableName, LogEventLevel.Warning, autoCreateSqlTable: false, columnOptions: columnOptions))
.CreateLogger();
此外,我添加了一个SerilogMiddleware,在管道中成功添加LogContext
中的HttpContext
。
在测试控制器中,我有以下两种测试方法:
public class TestController : ControllerBase
{
[HttpGet, Route("test")]
public IActionResult Get() {
try
{
string[] sar = new string[0];
var errorgenerator = sar[2]; // Trigger exception
}
catch (Exception ex)
{
Log.Error(ex, "Caught Exception");
return StatusCode(500, "Custom 500 Error");
}
return Ok();
}
[HttpGet, Route("test2")]
public IActionResult Get2() {
string[] sar = new string[0];
var errorgenerator = sar[2];// Trigger exception
return Ok();
}
}
第一种方法不是DRY,所以我想处理全局/未捕获的异常,例如方法2。
我的from here是:
public class GloablExceptionFilter : ActionFilterAttribute, IExceptionFilter
{
public void OnException(ExceptionContext context)
{
var httpContext = context.HttpContext; // This does not appear to have the actual HttpContext
Log.Error(context.Exception, "Unhandled Exception");
}
}
问题是,我的中间件,否则不再工作..它不编辑响应体等...此外,当我访问ExceptionContext的context.HttpContext
时,它不包含实际的HttpContext在上面的控制器方法中。
更新1:当前中间件
public void Configure(IApplicationBuilder app, IHostingEnvironment env, ILoggerFactory loggerFactory)
{
loggerFactory.AddSerilog();
app.UseAuthentication();
// Logging Middleware is just after Authentication, to have access to
// user IsAuthorized, claims, etc..
app.UseMiddleware<SerilogMiddleware>();
app.UseCors("CORSPolicy");
app.UseMvc();
}
在中间件本身:
public class SerilogMiddleware
{
readonly RequestDelegate _next;
public SerilogMiddleware(RequestDelegate next)
{
if (next == null) throw new ArgumentNullException(nameof(next));
_next = next;
}
public async Task Invoke(HttpContext httpContext)
{
// Do logging stuff with Request..
await _next(httpContext);
// Do logging stuff with Response but..
// This point is never reached, when exception is unhandled.
}
}
答案 0 :(得分:2)
基于代码片段,在向管道传递上下文时,您没有捕获异常。
如果您没有在中间件中捕获/处理异常,那么在调用流后它将无法访问您的代码。
public class SerilogMiddleware {
readonly RequestDelegate _next;
public SerilogMiddleware(RequestDelegate next) {
if (next == null) throw new ArgumentNullException(nameof(next));
_next = next;
}
public async Task Invoke(HttpContext httpContext) {
// Do logging stuff with Request..
try {
await _next(httpContext);
} catch(Exception ex) {
try {
//Do exception specific logging
// if you don't want to rethrow the original exception
// then call return:
// return;
} catch (Exception loggingException) {
//custom
}
// Otherwise re -throw the original exception
throw;
}
// Do logging stuff with Response
}
}
以上内容将在记录之后重新抛出原始错误,以便管道中的其他处理程序捕获它并进行开箱即用处理。