Question

我正在使用knockout并使用下面给出的自定义函数对控制器进行ajax调用。如果发生任何未处理的异常，它会返回整个页面作为响应，这会导致响应显示整个页面的html，请建议正确的处理方式

function asyncComputed(evaluator, owner) {
var result = ko.observable(), currentDeferred;
result.inProgress = ko.observable(false); // Track whether we're waiting for a result

ko.computed(function () {
    // Abort any in-flight evaluation to ensure we only notify with the latest value
    if (currentDeferred) { currentDeferred.reject(); }

    var evaluatorResult = evaluator.call(owner);
    // Cope with both asynchronous and synchronous values
    if (evaluatorResult && (typeof evaluatorResult.done == "function")) { // Async
        result.inProgress(true);

        currentDeferred = $.Deferred().done(function (data) {
            result.inProgress(false);
            if (data.hasOwnProperty("HasFailed") == true && data.ErrorCode == 1)//For Session Time Out 
            {
                $("#timeoutmessage")
                    .html('<div class="modal-backdrop">' +
                        '<div style="color:white;" class="middle">' +
                        '<div class="row-fluid"><div>Your session has timed out, please <a href="/">Login here </a>again.</div></div>' +
                        '</div>')
                    .show();

            }
            result(data);
        });
        evaluatorResult.done(currentDeferred.resolve);
    } else // Sync
        result(evaluatorResult);
});

return result;
}

我的调用函数是

  self.currentRevenue = asyncComputed(function () {
    self.currentRevenueinProgress(true);
    var duration = self.duration();
    var location = self.location();
    return $.ajax({
        url: getCurrentTotalRevenue,
        type: "GET",
        data: { "durationType": duration, "storeId": location }
    }).done(function (result) {
        self.currentRevenueinProgress(false);
        if (result.hasOwnProperty("HasFailed") == true) {
            self.currentRevenueError(true);
        }else{alert('success');}
    });

我正在使用asycComputed函数进行ajax调用，如果任何ajax调用异常所有ajax调用失败并导致页面的html响应。我可以在这里使用过滤器请建议

Answer 1

您可以在服务器上编写自定义操作过滤器，捕获异常并将其更改为JSON响应。

public class MyErrorHandlerAttribute : FilterAttribute, IExceptionFilter
{
    public void OnException(ExceptionContext filterContext)
    {
        filterContext.ExceptionHandled = true;
        filterContext.Result = new JsonResult
        {
            Data = new { success = false, error = filterContext.Exception.ToString() },
            JsonRequestBehavior = JsonRequestBehavior.AllowGet
        };
    }
}

然后您只需将自定义属性添加到控制器操作中。

处理未处理的异常MVC4 C＃knockout和ajax

1 个答案: