Question

在我的tableView中，我试图为每个字典显示某个类型的单元格，其中swapvalue等于0.这就是说，由于某种原因，下面的代码只会抓取第一个字典的值在我的数组中（ AKA： ）第一个字典中swapvalue的值为0，因此，我的表显示所有单元格，就好像后面的数组也有swapvalue 0 - 即使他们没有）。我怎样才能改变这一点，以便每个单元格从相应的字典中获取swapvalue？我怀疑它与indexPath.row有关，但我不确定如何纠正这个问题？

 - (int)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
    {


        if ([self.messageDataFriends count] > 0 ) {


            NSDictionary *userDictInfo = (NSDictionary*) [NSKeyedUnarchiver unarchiveObjectWithData:[[NSUserDefaults standardUserDefaults] objectForKey:@"diosSession"]];


            DIOSSession *session = [DIOSSession sharedSession];
            [session setUser:userDictInfo];


            [session user];


            NSString *targetedUser = [self.messageDataFriends objectForKey:@"uid2"];

            NSString *myID = [session user][@"user"][@"uid"];


            NSPredicate *p1 = [NSPredicate predicateWithFormat:@"uid contains[cd] %@", targetedUser];

            NSPredicate *p2 = [NSPredicate predicateWithFormat:@"targetuser contains[cd] %@", myID];

            NSPredicate *p3 = [NSPredicate predicateWithFormat:@"uid contains[cd] %@", myID];

            NSPredicate *p4 = [NSPredicate predicateWithFormat:@"targetuser contains[cd] %@", targetedUser];

            NSCompoundPredicate *pIntermediary1 = [NSCompoundPredicate andPredicateWithSubpredicates:@[p1, p2,]];

            NSCompoundPredicate * pIntermediary2 = [NSCompoundPredicate andPredicateWithSubpredicates:@[p3, p4,]];

            NSCompoundPredicate *pFinal = [NSCompoundPredicate orPredicateWithSubpredicates:@[pIntermediary1, pIntermediary2]];

            NSArray *filtered = [self.messages filteredArrayUsingPredicate:pFinal];


        return [filtered count];

            }


        else  {


            NSDictionary *userDictInfo = (NSDictionary*) [NSKeyedUnarchiver unarchiveObjectWithData:[[NSUserDefaults standardUserDefaults] objectForKey:@"diosSession"]];

            DIOSSession *session = [DIOSSession sharedSession];
            [session setUser:userDictInfo];


            [session user];

            NSString *targetedUser = [self.messageData objectForKey:@"uid"];

            NSString *myID = [session user][@"user"][@"uid"];


            NSPredicate *p1 = [NSPredicate predicateWithFormat:@"uid contains[cd] %@", targetedUser];

            NSPredicate *p2 = [NSPredicate predicateWithFormat:@"targetuser contains[cd] %@", myID];

            NSPredicate *p3 = [NSPredicate predicateWithFormat:@"uid contains[cd] %@", myID];

            NSPredicate *p4 = [NSPredicate predicateWithFormat:@"targetuser contains[cd] %@", targetedUser];

            NSCompoundPredicate *pIntermediary1 = [NSCompoundPredicate andPredicateWithSubpredicates:@[p1, p2,]];

            NSCompoundPredicate * pIntermediary2 = [NSCompoundPredicate andPredicateWithSubpredicates:@[p3, p4,]];

            NSCompoundPredicate *pFinal = [NSCompoundPredicate orPredicateWithSubpredicates:@[pIntermediary1, pIntermediary2]];

            NSArray *filtered = [self.messages filteredArrayUsingPredicate:pFinal];


          return [filtered count];


         }
    }



         - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
            {

                NSDictionary *data = self.messages[indexPath.section];

                id swapvalue = data[@"swapvalue"];
                NSLog(@"SWAP VALUE %@", swapvalue);

            if ([neighbours count] > 0 && [swapvalue isEqualToString: @"0"]) {

 static NSString *ChatTableIdentifier2 = @"SwapDetailTableViewCell";


        SwapDetailTableViewCell *cell = (SwapDetailTableViewCell *)[tableView dequeueReusableCellWithIdentifier:ChatTableIdentifier2 forIndexPath:indexPath];


          NSString *targetedUser = [self.messageData objectForKey:@"uid"];


          NSDictionary *userDictInfo = (NSDictionary*) [NSKeyedUnarchiver unarchiveObjectWithData:[[NSUserDefaults standardUserDefaults] objectForKey:@"diosSession"]];

          DIOSSession *session = [DIOSSession sharedSession];
          [session setUser:userDictInfo];


          [session user];


          NSString *myID = [session user][@"user"][@"uid"];

          NSPredicate *p1 = [NSPredicate predicateWithFormat:@"uid contains[cd] %@", targetedUser];

         NSPredicate *p2 = [NSPredicate predicateWithFormat:@"targetuser contains[cd] %@", myID];

          NSPredicate *p3 = [NSPredicate predicateWithFormat:@"uid contains[cd] %@", myID];

          NSPredicate *p4 = [NSPredicate predicateWithFormat:@"targetuser contains[cd] %@", targetedUser];

          NSCompoundPredicate *pIntermediary1 = [NSCompoundPredicate andPredicateWithSubpredicates:@[p1, p2,]];

          NSCompoundPredicate * pIntermediary2 = [NSCompoundPredicate andPredicateWithSubpredicates:@[p3, p4,]];

          NSCompoundPredicate *pFinal = [NSCompoundPredicate orPredicateWithSubpredicates:@[pIntermediary1, pIntermediary2]];

         NSArray *filtered = [self.messages filteredArrayUsingPredicate:pFinal];


          NSLog(@"WAT IS HERE 2 %@", filtered);

          NSString *userName = filtered[indexPath.row][@"first name"];
          cell.sendingUser.text = userName;

          NSString *messageBody = filtered[indexPath.row][@"body"];
          cell.messageDisplayed.text = messageBody;

          NSString *timeReceived = filtered[indexPath.row][@"published at"];
          cell.timeStamp.text = timeReceived;

      }

        return cell;

    }

Answer 1

根据您的代码，消息是一个字典数组，而不是数组字典。你在我的词典＆＃34;中谈到＆＃34; First数组，但那是错的。你只有1个数组。

如果数据不是字典数组，那么您发布的代码会崩溃。

我建议您记录messages结构，看看它真正包含的内容。

编辑：

您在编辑中发布的代码很乱。你应该不构建谓词和排序内容以响应任何表视图数据源方法。您应该在调用表视图时构建数据模型，然后不管它。

如果您有一个节表视图，则应该返回1以响应numberOfSections调用，并且所有单元格的数据将来自单个数组。

您的numberOfRowsInSection调用应该只查找该部分的数组中的项目数。

cellForRowAtIndexPath方法应从该（一）部分中的该行的数组中获取数据项，并使用它来填充单元格。

Answer 2

@Duncan关于一个数组是正确的。你有一个字典数组。现在你还需要看看 func tableView(UITableView, numberOfRowsInSection: Int) 和 func numberOfSections(in: UITableView) 如果你的数组中有numberOfSections ==项目数，则indexpath.row将始终为0.我怀疑这可能是问题所在。

Obj-C - 显示相应阵列中每个单元的正确数据

2 个答案:

编辑：