Question

我有一个string[]，值类似

string[] s = { "saravanan", "Karthick", "Jackson", "saravanan" };

我想看下面的输出

saravanan发生2次
  卡尔提克出现过1次
  杰克逊发生过1次

如何不使用 List或Dictionary

这是我到目前为止尝试过的：

int i, j;
String[] s = {"saravanan", "Karthick", "Jackson", "saravanan"}

Console.WriteLine("Number of Times occured Each Values");

for (i = 0; i < s.Length; i++)
{
    int count = 0;
    for (j = 0; j < s.Length; j++)
    {
        if (s[i] == (s[j]))
        {
            count++;
        }
    }

    Console.WriteLine(s[i]+"is count="+count);
}

该代码产生以下输出：

每个值出现的次数
  saravananis count = 2
  Karthickis count = 1
  杰克逊（Jacksonis）count = 1
  saravananis count = 2

Answer 1

通常，我们通过 Linq

解决此类问题（查询）

  string[] s = new[] { 
    "saravanan", "Karthick", "Jackson", "saravanan" };

  var result = string.Join(Environment.NewLine, s
    .GroupBy(item => item)
    .Select(chunk => $"{chunk.Key} occures {chunk.Count()} times"));

  Console.Write(result);

在嵌套循环（您当前的代码）的情况下，不要打印几次相同的名称。让我们介绍一下bool appeared，如果名字之前出现过

   string[] s = new[] { 
     "saravanan", "Karthick", "Jackson", "saravanan" };

   for (i = 0; i < s.Length; i++) {
     int count = 0;
     bool appeared = false;

     for (j = 0; j < s.Length; j++) {
       if (s[i] == (s[j])) {
         // Names are same. Do we have the name before?
         if (j < i) {
           // If yes we have no need to loop any more
           appeared = true;

           break;
         }

         count++;
       }
     }

    // if name has been appeared already we shouldn't print it out 
    if (!appeared) 
      Console.WriteLine(s[i] + "is count=" + count);
  }

Answer 2

由于您不希望"saravanan"在输出中出现两次。然后，您可以使用一个空字符串作为前哨值。当您发现增加计数的匹配项时，请将该元素清空，并进行检查以在以后运行时跳过该元素。

using System;

public class Program
{   
    public static void Main()
    {
        string[] s = { "saravanan","KArthick","Jackson","saravanan" };
        for (int i = 0; i < s.Length; i++) 
        {
            // Skip empty element
            if (string.IsNullOrEmpty(s[i]))
            {
                continue;
            }

            int count = 1;
            for (int j = i + 1; j < s.Length; j++) 
            {
                // Skip empty element
                if (string.IsNullOrEmpty(s[i]))
                {
                    continue;
                }

                if (s[i] == s[j])
                {
                    count++;

                    // Clear the element to indicate the element as already been counted
                    s[j] = string.Empty; 
                }
            }

            Console.WriteLine("{0} occurs {1} times", s[i], count);
        }
    }
}

结果

saravanan occurs 2 times
KArthick occurs 1 times
Jackson occurs 1 times

Fiddle Demo

Answer 3

您可以使用linq组选项，如下所示：

 String[] s = {"saravanan", "Karthick", "Jackson", "saravanan"};

        Console.WriteLine("Number of Times occured Each Values");

        var groupArray = s.GroupBy(x => x);
        foreach (var group in groupArray)
        {
            Console.WriteLine(group.Key + "is count=" + group.Count());

        }

显示数组中的每个值Count

3 个答案: