Question

我想知道是否有可能通过属性名称获取数组的元素而不是位置。例如，这是我的传入数据：

    {
    "salesdata": {
        "productsbyzone": {
            "zones": [{
                    "eastzone": "shirts, trousers"
                },
                {
                    "westzone": "slacks"
                },
                {
                    "northzone": "gowns"
                },
                {
                    "southzone": "maxis"
                }
            ]
        }
    }
}

我打算将它移到SQL数据库中，我在每个区域的数据库中都有列。问题是不同区域的顺序在每个json内发生变化。我成功地使用了以下查询，直到我意识到区域的位置在每个json中发生变化：

WITH 
salesData AS
(
    SELECT
    (c.salesdata.productsbyzone.zone,0) as eastzone,
    (c.salesdata.productsbyzone.zone,1) as westzone,
    (c.salesdata.productsbyzone.zone,2) as northzone,
    (c.salesdata.productsbyzone.zone,3) as sourthzone,
    FROM [sales-data] as c
)
SELECT
eastzone.eastzone as PRODUCTS_EAST,
westzone.westzone as PRODUCTS_WEST,
northzone.northzone as PRODUCTS_NORTH,
southzone.southzone as PRODUCTS_SOUTH
INTO PRODUCTSDATABASE
FROM salesData

需要一种方法来通过名称而不是位置来引用这些字段。

Answer 1

您可以使用DateFormatter返回数组元素，然后访问每个属性。请参考以下查询

let dateFormatter = DateFormatter()

dateFormatter.dateFormat = "MMMM '\(String(describing: day!)),' yyyy h:mm a"

let dateString = "\(dateFormatter.string(from: date))"

print(dateString)

Answer 2

我建议使用解决方案：使用azure流作业中的JavaScript UDF来完成列排序。

请参阅我的样本：

输入数据（扰乱订单）：

git log --ancestry-path BRANCH..MASTER

js udf code：

{
    "salesdata": {
        "productsbyzone": {
            "zones": [{
                    "westzone": "slacks"  
                },
                {
                    "eastzone": "shirts, trousers"
                },
                {
                    "northzone": "gowns"
                },
                {
                    "southzone": "maxis"
                }
            ]
        }
    }
}

您可以在function test(arg) { var z = arg; var obj = { eastzone: "", westzone: "", northzone: "", southzone: "" } for(var i=0;i<z.length;i++){ switch(Object.keys(z[i])[0]){ case "eastzone": obj.eastzone = z[i]["eastzone"]; continue; case "westzone": obj.westzone = z[i]["westzone"]; continue; case "northzone": obj.northzone = z[i]["northzone"]; continue; case "southzone": obj.southzone = z[i]["southzone"]; continue; } } return obj; }参数

中定义所需的顺序

<强> SQL：

obj

<强> 输出：

希望它对你有所帮助。

Azure流分析：按名称获取数组元素

2 个答案: