Question

我的ViewModel实现了serializable，我已经定义了按钮点击方法，如下所示..

public class FragmentHomeViewModel
 extends BaseObservable 
implements Serializable {
private Rerofit retrofit;
private HomeScreen activity;

public FragmentHomeViewModel(HomeScreen activity) {

        this.activity = activity;
        retrofit = MyGlobal.getMyGlobale(activity).getNetComponent().retrofit();

    }
//
//....code

 public void onClickCuisine(View view){
         Intent intent = new Intent(view.getContext(), SelectCuisineActivity.class);
            (view.getContext()).startActivity(intent);
       Log.e("is clicked"," may be");
    }


}

这是我用这个视图模型附加的xml类

<?xml version="1.0" encoding="utf-8"?>
<layout   xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    >
    <data class="Item4DataMindingCuisine">
        <import type="com.aman.camellia.kniterider.utils.Constrants" />
        <variable
            name="index"
            type="int"/>
        <variable
            name="viewModel"
            type="com.aman.camellia.kniterider.viewmodel.FragmentHomeViewModel"/>
    </data>
    <RelativeLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_marginBottom="@dimen/dim6dp"
        android:layout_marginLeft="@dimen/dim10dp">

        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_alignParentEnd="true"
            android:layout_marginBottom="8dp"
            android:layout_marginEnd="8dp"
            android:layout_marginTop="8dp"
            android:text="View All"
            android:textColor="@color/colorPrimary"
            android:textSize="@dimen/text16sp"
            android:onClick="@{viewModel::onClickCuisine}"
            app:fontText="@{Constrants.BOLD_FONT}"
          />

    </RelativeLayout>

</layout>

现在在textview上点击我正在

java.lang.RuntimeException：Parcelable遇到IOException写入可序列化对象（name = com.aman.camellia.kniterider.viewmodel.FragmentHomeViewModel）

 Caused by: java.io.NotSerializableException: retrofit2.Retrofit$1

知道为什么会出现这个错误。我认为这个错误的原因可能是我使用过的改造（实际上我使用了匕首）。

Answer 1

好吧最后我得到了答复。出现这个问题的原因是，我的viewmodel实现了Serializable和retrofit实例没有被序列化，所以你需要序列化改造或者将改进变量作为瞬态变量来进行序列化。之后我的观点模型将是......

public class FragmentHomeViewModel
 extends BaseObservable 
implements Serializable {
transient Rerofit retrofit;
private HomeScreen activity;

public FragmentHomeViewModel(HomeScreen activity) {

        this.activity = activity;
        retrofit = MyGlobal.getMyGlobale(activity).getNetComponent().retrofit();

    }
//
//....code

 public void onClickCuisine(View view){
         Intent intent = new Intent(view.getContext(), SelectCuisineActivity.class);
            (view.getContext()).startActivity(intent);
       Log.e("is clicked"," may be");
    }


}

这样做另一项活动成功开始。

Parcelable遇到IOException，编写由java.io.NotSerializableException引起的可序列化对象：retrofit2.Retrofit $ 1

1 个答案: