def main():
l=[]
for i in range(1981,2018):
df = pd.read_csv("ftp://ftp.cpc.ncep.noaa.gov/htdocs/degree_days/weighted/daily_data/"+ str(i)+"/Population.Heating.txt")
print(df[12:])
我试图从1981年到2017年下载并阅读Population.Heating.txt中的“CONUS”行。 我的代码似乎得到了CONUS部分,但我怎么能像csv格式一样读取它?|
谢谢!
答案 0 :(得分:2)
试试这个:
def main():
l=[]
url = "ftp://ftp.cpc.ncep.noaa.gov/htdocs/degree_days/weighted/daily_data/{}/Population.Heating.txt"
for i in range(1981,2018):
df = pd.read_csv(url.format(i), sep='\|', skiprows=3, engine='python')
print(df[12:])
演示:
In [14]: url = "ftp://ftp.cpc.ncep.noaa.gov/htdocs/degree_days/weighted/daily_data/{}/Population.Heating.txt"
In [15]: i = 2017
In [16]: df = pd.read_csv(url.format(i), sep='\|', skiprows=3, engine='python')
In [17]: df
Out[17]:
Region 20170101 20170102 20170103 20170104 20170105 20170106 20170107 20170108 20170109 ... 20171222 20171223 \
0 1 30 36 31 25 37 39 47 51 55 ... 40 32
1 2 28 32 28 23 39 41 46 49 51 ... 31 25
2 3 34 30 26 43 52 58 57 54 44 ... 29 32
3 4 37 34 37 57 60 62 59 54 43 ... 39 45
4 5 15 11 9 10 20 21 27 36 33 ... 12 7
5 6 16 9 7 22 31 38 45 44 35 ... 9 9
6 7 8 5 9 23 23 34 37 32 17 ... 9 19
7 8 30 32 34 33 36 42 42 31 23 ... 36 33
8 9 25 25 24 23 22 25 23 15 17 ... 23 20
9 CONUS 24 23 21 26 33 38 40 39 34 ... 23 22
20171224 20171225 20171226 20171227 20171228 20171229 20171230 20171231
0 32 34 43 53 59 59 57 59
1 30 33 43 49 54 53 50 55
2 41 47 58 62 60 54 54 60
3 47 55 61 64 57 54 62 68
4 12 20 21 22 27 26 24 29
5 22 33 31 35 37 33 32 39
6 19 24 23 28 28 23 19 27
7 34 30 32 29 26 24 27 30
8 18 17 17 15 13 11 12 15
9 26 30 34 37 38 35 34 40
[10 rows x 366 columns]
答案 1 :(得分:1)
def main():
l=[]
for i in range(1981,2018):
l.append( pd.read_csv("ftp://ftp.cpc.ncep.noaa.gov/htdocs/degree_days/weighted/daily_data/"+ str(i)+"/Population.Heating.txt"
, sep='|', skiprows=3))
文件看起来像:
Product: Daily Heating Degree Days
Regions: Regions::CensusDivisions
Weights: Population
[... data ...]
所以你需要跳过3行。之后你会有几个' df'在你的清单中' l'进一步处理。