Question

我有以下数据

PET_REF XDATE       TYPE
123     01/01/2017  OBJ
123     01/01/2017  OBJ
123     01/01/2017  OBJ
123     02/01/2017  LVE
456     01/01/2017  OBJ
456     01/01/2017  LVE
456     02/01/2017  OBJ

是否可以仅返回最新（按XDATE）TYPE不是LVE的PET_REF行

因此，对于上面的数据，输出应为

PET_REF XDATE       TYPE
456     01/01/2017  OBJ
456     01/01/2017  LVE
456     02/01/2017  OBJ

Answer 1

使用FIRST_VALUE分析函数

Select * from 
(
select PET_REF, XDATE, TYPE, First_Value(TYPE)over(Partition by PET_REF order by XDATE desc) as Latest_Type
from yourtable 
)a
Where Latest_Type <> 'LVE'

SQLFIDDLE DEMO

Answer 2

解决此问题的一种方法是尝试将它们放在子查询中。

SELECT * 
FROM t 
WHERE c1 IN (
             SELECT c1 
             FROM t
             WHERE (c1,c2) IN (SELECT c1, MAX(c2) 
                               FROM t 
                               GROUP BY 1)
             AND c3 <> 'LVE');

Answer 3

这是一个选项：

SQL> with test (pet_ref, xdate, type) as
  2    (select 123, date '2017-01-01', 'obj' from dual union all
  3     select 123, date '2017-01-01', 'obj' from dual union all
  4     select 123, date '2017-01-01', 'obj' from dual union all
  5     select 123, date '2017-01-02', 'lve' from dual union all  --
  6     select 456, date '2017-01-01', 'obj' from dual union all
  7     select 456, date '2017-01-01', 'lve' from dual union all  --
  8     select 456, date '2017-01-02', 'obj' from dual
  9    ),
 10  inter as
 11    (select pet_ref, type,
 12            rank() over (partition by pet_ref order by xdate desc) rnk
 13     from test
 14    )
 15  select * from test t
 16  where t.pet_ref not in (select i.pet_ref from inter i
 17                          where i.rnk = 1
 18                            and i.type = 'lve');

   PET_REF XDATE      TYP
---------- ---------- ---
       456 02/01/2017 obj
       456 01/01/2017 lve
       456 01/01/2017 obj

SQL>

Answer 4

通过以下方式使用订单更容易实现此目的：

SELECT *
FROM datatable
WHERE PET_REF LIKE (SELECT MAX(PET_REF) FROM datatable)
ORDER BY XDATE ASC, TYPE DESC;

尝试SQLFiddle

只返回日期最大的行和一个额外的标准

4 个答案: