Question

按钮点击后我需要$randNum变量值。但是当单击该按钮时，该值会更改。当它的回显值与点击按钮后的表插入值不同。

<input type="submit" class="btn btn-success btn-signin" 
       onClick="printDiv();" name="trConfirmed" id="trConfirmed" value="Print"  />

<?php
$randNum = mt_rand(10, 100000);
echo($randNum); //I want to echo the $randNum here.
?>

<?php
/* ---- IF TRANSCATION CONFIRM BUTTON CLICK--- */
if (isset($_POST['trConfirmed'])) {

    $sqlInsertInToTr = "INSERT INTO transactions (date_t,transaction_id,item_code,item_name,description,quantity,p_cost,sale_price,total_price)
                        SELECT CURDATE(),$randNum,item_code,item_name,description,quantity,p_cost,sale_price,total_price FROM tem_transaction ";
    if ($db->dbQuery($sqlInsertInToTr)) {   //need same $randNum value here
        //echo("Transaction Confirmed-----");
        echo "<meta http-equiv='refresh' content='0'>";
    }
    $deletFrmTmTr = "TRUNCATE tem_transaction";
    if ($db->dbQuery($deletFrmTmTr)) {
        //echo("deleted.........");
    }
}
?>

Answer 1

如果发出POST和GET请求，将执行$ randNum值的打印代码。也许，在POST请求执行后，您会看到请求的GET结果。在浏览器中跟踪有多少地址发生在php到该代码的文件

点击按钮后需要PHP变量值

1 个答案: