单击后删除按钮

Question

我有一个页面，用户可以在其中查看他们的请假申请，旁边还有一个取消按钮，如下所示：

View Page

我想要发生的是，当我点击取消按钮时，状态会改变，按钮会消失。

我添加了一个脚本，该按钮会使按钮消失并且有效，但它不会更新状态。

所以这是我的表格：

<div class="container">
<div class="page-header">
<h3>My Leaves</h3>
			<div class="table-responsive">
				<table class="table">
					<tr>
						<th>Employee Name</th>
						<th>Phone</th>
						<th>Email</th>
						<th>From</th>
						<th>To</th>
						<th>Reason</th>
						<th>Type</th>
						<th>Status</th>
					</tr>
				<?php
					include ('database.php');
					$result = $database->prepare ("SELECT leaves.* FROM leaves INNER JOIN employee ON employee.id = leaves.user_id WHERE employee.username = '".$_SESSION["VALID_USER_ID"]."'");
					$result ->execute();
					for ($count=0; $row_message = $result ->fetch(); $count++){
				?>
					<tr>
						<td><?php echo $row_message['firstname']." " .$row_message['lastname']; ?></td>
						<td><?php echo $row_message['phone']; ?></td>
						<td><?php echo $row_message['email']; ?></td>
						<td><?php echo $row_message['fromdate']; ?></td>
						<td><?php echo $row_message['todate']; ?></td>
						<td><?php echo $row_message['reason']; ?></td>
						<td><?php echo $row_message['type']; ?></td>
						<td><?php echo $row_message['status']; ?></td>
						<td>
							<form method="post" action="update-leave-status-emp.php">
								<input type="hidden" name="leaveno" value="<?php echo $row_message['leaveno']; ?>" />
								<input type="submit" value="Cancelled" class="removebtn" name="cancelled"></input>
							</form>
						</td>
					</tr>
					<?php	}	?>
					
					</table>
					
					<a href="employee_panel.php"><button type="button" class="btn btn-primary"><i class="glyphicon glyphicon-arrow-left"></i> Back</button></a>	
				</div>
			</div>
		</div>	
	</div>
</div>

以下是以下脚本：

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
	<script>
			$(document).ready(function(){
			$(".removebtn").click(function(){
			$(this).remove();
		});
	});
</script>

PHP代码：

<?php

	 if(isset($_POST['cancelled']))
    {
        $msg = "Cancelled";
        $status=$_POST['cancelled'];
    }
    $leaveno=$_POST['leaveno'];
    $con = mysqli_connect('localhost', 'root', '');
    mysqli_select_db($con, 'companydb');

    $sql = "UPDATE leaves SET status = '$status' WHERE leaveno = '$leaveno'";

    if(mysqli_query($con, $sql))
        header("refresh:1; url=view-leave-emp.php?msg=$msg");
    else
        var_dump(mysqli_error($con));
	
?>