我正在尝试使用firebase身份验证/数据库为反应原生移动应用创建登录和注册过程。
我可以使用Login.js中的预先存在的电子邮件/密码成功登录。
当我尝试在SignUp.js
中创建新帐户时,我的问题就出现了用户已正确添加到firebase身份验证中,但我希望我的用户个人资料可以获得更多信息。这就是为什么我用他们的名字,电子邮件和我从Signup.js第33行代码中删除的其他信息写入数据库的原因,第52行有辅助函数。
我的错误是undefined is not an object(evaluating this.state.email)
,来自SignUp.js的第33行
这对我没有意义,因为我可以使用this.state.email
this.state.email
是否超出范围?任何帮助是极大的赞赏。
App.js
import React from 'react';
import { StackNavigator } from 'react-navigation';
import * as firebase from 'firebase';
import Dashboard from './components/Dashboard';
import Login from './components/Login';
import SignUp from './components/SignUp';
const Application = StackNavigator({
Login: { screen: Login},
SignUp: { screen: SignUp},
Dashboard: { screen: Dashboard },
});
export default class App extends React.Component {
componentWillMount(){
const firebaseConfig = {
apiKey: 'MY KEY',
authDomain: 'MY DOMAIN',
databaseURL: 'MY DATABASE URL',
}
if (!firebase.apps.length) {
firebase.initializeApp(firebaseConfig);
}
}
render() {
return (
<Application/>
)}}
Login.js
import React from 'react';
import { StyleSheet, Text, View, KeyboardAvoidingView, ImageBackground } from 'react-native';
import { StackNavigator } from 'react-navigation';
import { Button } from 'react-native-elements';
import { Input } from './Input';
import Dashboard from './Dashboard';
import * as firebase from 'firebase';
export default class Login extends React.Component {
constructor(props){
super(props)
this.state = {
email: '',
password: '',
}
}
loginUser = (email, password, navigate) => {
try{
firebase.auth().signInWithEmailAndPassword(email, password)
.then(function(user){
console.log(user);
navigate('Dashboard', {email, password});
})
}
catch (error){
alert('No known user for that email and password combination')
console.log(error.toString());
}
}
static navigationOptions = { header: null }
render() {
const{ navigate } = this.props.navigation;
return (
<KeyboardAvoidingView
behavior='padding'>
<Input
placeholder = 'Email'
onChangeText = {email => this.setState({email})}
value = {this.state.email}/>
<Input
placeholder = 'Password'
secureTextEntry
onChangeText = {password => this.setState({password})}
value = {this.state.password}/>
<Button
title = 'Log in'
onPress = {() => this.loginUser(this.state.email, this.state.password, navigate)}/>
<Button
title = 'Sign up'
onPress = {() => navigate('SignUp')}/>
</KeyboardAvoidingView>
);
}
}
SignUp.js
import React from 'react';
import { StyleSheet, Text, View, KeyboardAvoidingView, ImageBackground } from 'react-native';
import { StackNavigator } from 'react-navigation';
import { Button } from 'react-native-elements';
import { Input } from './Input';
import Dashboard from './Dashboard';
import * as firebase from 'firebase';
export default class SignUp extends React.Component {
constructor(props){
super(props)
this.state = {
firstName: '',
lastName: '',
email: '',
password: '',
confirmPassword: '',
}
}
signUpUser = () => {
try{
if(this.state.password === this.state.confirmPassword){
console.log('CREATING USER...');
firebase.auth().createUserWithEmailAndPassword(this.state.email, this.state.password).then( response => {
console.log('SIGNING IN...');
firebase.auth().signInWithEmailAndPassword(this.state.email, this.state.password)
firebase.auth().onAuthStateChanged(function(user) {
if (user) {
console.log('WRITING TO DATABASE...');
this.writeUserData(user, this.state.email, this.state.firstName, this.state.lastName);
}
else {
alert('Something went wrong. Please try again.');
return;
}
});
})
}
else{
alert('Passwords do not match');
return;
}
}
catch(error){
console.log(error.toString());
}
}
writeUserData = (user, email, first, last) => {
console.log('ADDING USER ' + user.uid)
try{
firebase.database().ref('users/' + user.uid).set({
email: email,
first: first,
last: last,
});
}
catch(error){
console.log(error.toString());
}
console.log('WRITE COMPLETE')
//navigate to dashboard
}
static navigationOptions = { header: null }
render() {
const{ navigate } = this.props.navigation;
return (
<KeyboardAvoidingView
behavior='padding'>
<Input
placeholder = 'First Name'
onChangeText = {firstName => this.setState({firstName})}
value = {this.state.firstName}/>
<Input
placeholder = 'Last Name'
onChangeText = {lastName => this.setState({lastName})}
value = {this.state.lastName}/>
<Input
placeholder = 'Email'
onChangeText = {email => this.setState({email})}
value = {this.state.email}/>
<Input
placeholder = 'Password'
secureTextEntry
onChangeText = {password => this.setState({password})}
value = {this.state.password}/>
<Input
placeholder = 'Confirm password'
secureTextEntry
onChangeText = {confirmPassword => this.setState({confirmPassword})}
value = {this.state.confirmPassword}/>
<Button
title = 'Create Account'
onPress = {() => this.signUpUser()}/>
<Text
activeOpacity={0.75}
onPress = {() => this.props.navigation.goBack()}>
Go back
</Text>
</KeyboardAvoidingView>
);
}
}
答案 0 :(得分:7)
this
处于不同的功能时,它会改变意义。这基本上是对象方法在Javascript中工作的原因,因为this
总是引用包含它的类。当您在匿名函数中使用this
时,就像在SignUp.js
文件中一样,您没有像以前那样使用相同的this
。
一个简单的解决方法是添加如下行:
let self = this;
或者,如果您只需要州:
let state = this.state;
之前 firebase.auth().onAuthStateChanged(function(user) {
位。然后在里面,你使用你创建的变量而不是this
。
要尝试的另一件事是将匿名function
更改为箭头功能。箭头函数不会修改this
变量。所以,像:
firebase.auth().onAuthStateChanged((user) => {
答案 1 :(得分:0)
尝试使用普通的javascript函数进行回调而不是使用ES6胖箭头。
而不是
response => {...}
使用
function(response){...}
this article可能会帮助您更多地了解胖箭头功能的范围。