Question

我首先查询数据库以获取与某个用户标识关联的所有记录，然后我需要进入并修改数组，因为其中一个字段是一个id，我需要与该id关联的名称。< / p>

所以我使用columnCount在id的索引处迭代生成的数组，并用正确的名称替换它，对于前六个结果，它正常工作。 columnCount只返回6，但前六个会重命名，因为它们应该是。但除此之外，它需要来自该pdostatement的结果并正常填充表格，所有相关数据，现在是17行。

为什么它会返回6，或者我在做什么来获得错误的列数？

global $__CMS_CONN__;
    $timeqry = 'SELECT facility_id, program, date, visit_length, mileage, served FROM timesheet_db WHERE volunteer_id = '.$_SESSION['user_id'];
    $stmt = $__CMS_CONN__->prepare($timeqry);
    $stmt->execute();
    $columns = $stmt->columnCount();
    print $columns;
    if($stmt)
    {
        $arrValues = $stmt->fetchAll(PDO::FETCH_ASSOC);

        for($x=0;$x<$stmt->columnCount();$x++)
        {
            global $__CMS_CONN__;
            $qry = 'SELECT facility FROM facility_db WHERE id = '.$arrValues[$x]['facility_id'];
            $stmt1 = $__CMS_CONN__->prepare($qry);
            $stmt1->execute();
            if($stmt1)
            {
                $facilityName = $stmt1->fetchAll(PDO::FETCH_ASSOC);
                foreach ($facilityName as $item)
                {
                    foreach ($item as $key => $val)
                    {
                        $arrValues[$x]['facility_id'] = $val;
                    }
                }
            }
        }
        print "<table style=\"font-size:90%\">\n";
        print "<tr>\n";
        print "<th style=\"width:100%\">Facility</th>";
        print "<th>Program</th>";
        print "<th>Date</th>";
        print "<th>Visit Length</th>";
        print "<th>Mileage</th>";
        print "<th>Served</th>";
        print "</tr>";
        foreach ($arrValues as $row)
        {
            print "<tr>";
            foreach ($row as $key => $val)
            {
                print "<td>$val</td>";
            }
            print "</tr>\n";
        }
        print "</table>\n";
    }

Answer 1

您在第一个SELECT查询中询问了六列：

SELECT facility_id, program, date, visit_length, mileage, served FROM timesheet_db WHERE volunteer_id = $_SESSION['user_id']

因此，columnCount()当然是6.它不会将列数乘以返回的行数或类似的行数。

如果您想要行的数量，则需要count($arrValues)（手册中说rowCount()的数据库行为与SELECT s}不一致。

为什么PDOStatement-＆gt; columnCount没有返回正确的数字？

1 个答案: