Question

我有一张桌子＆＃34; bon_sav＆＃34;其id具有递增序列（＆＃34; bon_sav_id_seq＆＃34;）

还创建了另一个名为＆＃34; hibernate_sequence＆＃34;

的序列

我的问题是我的桌子＆＃34; bon_sav＆＃34;使用序列＆＃34; hibernate_sequence＆＃34;而不是＆＃34; bon_sav_id_seq＆＃34;。我有其他表使用这个序列＆＃34; hibernate_sequence＆＃34;所以我可能很快就会遇到问题。

有create table bon_sav

的脚本

CREATE TABLE bon_sav (
id bigint NOT NULL,
uuid character varying(40) NOT NULL,
logiciel_id character varying(40) NOT NULL,
code_magasin character varying(10),
numero_fournisseur character varying(40),
date_depot date NOT NULL,
date_retrait date,
code_client character varying(10) NOT NULL,
nom_client character varying(30),
prenom_client character varying(30),
email_client character varying(50),
telephone_client character varying(20),
url_photo character varying(255),
date_creation timestamp without time zone NOT NULL,
date_modification timestamp without time zone,
date_suppression timestamp without time zone,
est_supprimer boolean,
entite_id bigint,
nature_id bigint,
type_id bigint,
lieu_id bigint,
etat_id bigint,
destinataire_id bigint,
createur_id bigint,
modificateur_id bigint,
supprimeur_id bigint,
nom_produit character varying(100) DEFAULT ' '::character varying NOT NULL,
detail_produit text
);


ALTER TABLE bon_sav OWNER TO yvidya;

--
-- TOC entry 222 (class 1259 OID 16594)
-- Name: bon_sav_id_seq; Type: SEQUENCE; Schema: public; Owner: yvidya
--

CREATE SEQUENCE bon_sav_id_seq
    START WITH 1
    INCREMENT BY 1
    NO MINVALUE
    NO MAXVALUE
    CACHE 1;


ALTER TABLE bon_sav_id_seq OWNER TO yvidya;

--
-- TOC entry 2279 (class 0 OID 0)
-- Dependencies: 222
-- Name: bon_sav_id_seq; Type: SEQUENCE OWNED BY; Schema: public; Owner: yvidya
--

ALTER SEQUENCE bon_sav_id_seq OWNED BY bon_sav.id;


--
-- TOC entry 2143 (class 2604 OID 16599)
-- Name: bon_sav id; Type: DEFAULT; Schema: public; Owner: yvidya
--

ALTER TABLE ONLY bon_sav ALTER COLUMN id SET DEFAULT nextval('bon_sav_id_seq'::regclass);

在Java中，在我的课堂上，我有：

@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
@SequenceGenerator(name = "sequenceGenerator")
private Long id;

你知道为什么这是正确使用的序列吗？

Answer 1

请看这个解决方案：Configure JPA to let PostgreSQL generate the primary key value

尝试提及序列名称如下（参见链接中的完整解决方案）：

@Id
@SequenceGenerator(name="webuser_idwebuser_seq",
                   sequenceName="webuser_idwebuser_seq",
                   allocationSize=1)
@GeneratedValue(strategy = GenerationType.SEQUENCE,
                generator="webuser_idwebuser_seq")
@Column(name = "idwebuser", updatable=false)
private Integer id;

我不知道继续创建序列的最佳方法是什么，但您可以让Postgresql根据链接

中的建议使用 SERIAL 类型生成它

为什么postgresql没有使用正确的序列？

1 个答案: