Question

我无法理解为什么解编。

这是我的班级：

@XmlRootElement(name = "privileges")
@XmlAccessorType(XmlAccessType.FIELD)
public  class Privilege {
    @XmlAttribute(name = "number_residents")
    private Integer numberResidents;
    @XmlAttribute(name = "value")
    private String value;
    @XmlElement(name = "privilege")
    private String privilage;

下面有getter，setter，equals和toString }

我正在尝试解组。

 File file = new File( "response.xml");
                JAXBContext context = JAXBContext.newInstance(Privilege.class);
                Unmarshaller unmarshaller = context.createUnmarshaller();
                Privilege privilege = (Privilege) unmarshaller.unmarshal(file);
                System.out.println(privilege);

但我总是得到：

Privilege{numberResidents=null, value='null', privilage='Test privilege'}

但是在这样的文件中：

<?xml version="1.0" encoding="UTF-8"?>
<privileges>
    <privilege number_residents="3" value="bb2">Test privilege</privilege>
</privileges>

我需要你的帮助

Answer 1

您的映射不正确。

尝试：

@XmlRootElement(name = "privileges")
@XmlAccessorType(XmlAccessType.FIELD)
public class Privileges {

    @XmlElement(name="privilege")
    private Privilege privilege;

    //Getters and setters

}

@XmlAccessorType(XmlAccessType.FIELD)
public class Privilege{

    @XmlAttribute(name = "number_residents")
    private Integer numberResidents;
    @XmlAttribute(name = "value")
    private String value;
    @XmlValue
    private String privilege;

    //getters and setters

}

错误发生在解组中

1 个答案: