Question

我正在尝试解组现有的xml文件，以便我可以正确处理数据，但XML结构看起来很奇怪。下面是xml的示例以及我创建的对象。

<?xml version="1.0" encoding="UTF-8"?> 
<Record>
<identifier>11</identifier>
<TotalRecords>266</TotalRecords>
<ListOfSections>
    <SECTION>AA1001</SECTION>
    <ListOfStudents>
        <SequenceNumber>11</SequenceNumber>
        <RecordCount>1</RecordCount>
        <StudentId>201614354</StudentId>

    </ListOfStudents>

    <SECTION>AA1002</SECTION>
    <ListOfStudents>
        <SequenceNumber>15</SequenceNumber>
        <RecordCount>1</RecordCount>
        <StudentId>201614356</StudentId>

        <SequenceNumber>16</SequenceNumber>
        <RecordCount>2</RecordCount>
        <StudentId>201614355</StudentId>
    </ListOfStudents>
</ListOfSections>
</Record>

以下是我的java课程。我刚刚删除了变量以便于阅读。

@XmlRootElement
public class Record {

    @XmlElement(name = "TotalRecords")
    public Integer getTotalNoOfRecords() {
        return totalNoOfRecords;
    }

    @XmlElement(name = "ListOfSections")
    public List<Section> getSectionList() {
        return sectionList;
    } 
}


@XmlRootElement
public class Section {

    @XmlElement(name = "SECTION")
    public String getSection() {
        return section;
    }

    @XmlElement(name = "ListOfStudents")
    public List<Student> getStudentList() {
        return studentList;
    }
}


@XmlRootElement
public class Student {

    @XmlElement(name = "SequenceNumber")
    public Integer getSequenceNumber() {
        return sequenceNumber;
    }

    @XmlElement(name = "RecordCount")
    public Integer getRecordCount() {
        return recordCount;
    }

    @XmlElement(name = "StudentId")
    public Integer getStudentId() {
        return studentId;
    }
}

我试图获取ListOfSections标签中的所有记录，但我只得到AA1002的最后一部分。

对于ListOfStudents的

我只获得了我的第一条记录我只获得序列号为15的记录

<SequenceNumber>12</SequenceNumber>
<RecordCount>2</RecordCount>
<StudentId>201614355</StudentId>

Answer 1

这个简化的代码适用于你的xml，它应该给你一个提示，在哪里寻找问题：

class Record {
    @XmlElementWrapper(name="ListOfSections")
    @XmlElement(name="SECTION")
    List<String> listOfSections;
}

这里如何运行：

    Record r = JAXB.unmarshal(new File("1.xml"), Record.class);
    System.out.println(r.listOfSections);

结果：

[AA1001, AA1002]

解组XML

1 个答案: