Question

以下是我需要提取信息的小数据快照。

ID      FREQ      LTD          SD           LWD     DPD
_______________________________________________________
1021    Weekly  2016-05-27  2016-05-23  2016-05-31  0
1021    Weekly  2016-05-27  2016-05-27  2016-05-31  0
1021    Weekly  2016-06-02  2016-06-06  2016-06-30  24
1021    Weekly  2016-06-02  2016-06-13  2016-06-30  17
1021    Weekly  2016-06-02  2016-06-20  2016-06-30  10
1021    Weekly  2016-06-02  2016-06-27  2016-06-30  0
1021    Weekly  2017-02-27  2017-02-06  2017-02-28  0
1021    Weekly  2017-02-27  2017-02-13  2017-02-28  0

LTD =该月的最后交易日期

SD =付款应该到来的那个月的预定日期。

LWD =该月的最后工作日。

DPD =过去天数，计算方式为 when freq = 'Weekly' and SD between LTD and LWD AND datediff(LWD, SD) > 7 THEN datediff(LWD, SD) as DPD。所有日期都是日期数据类型。

现在，请参阅示例数据并注意第6行和第7行。第7行将DPD计算为0，同时考虑LWD和＆＃39; SD＆＃39;当月但是，考虑到2016-06-02下一次付款2017-02-27之后，应该计算DPD，因此在DPD计算中，应该在未进行交易的未来6个月内添加天数。

我怎样才能做到这一点？任何帮助赞赏。

我目前的查询是：

select y.*,
      case when freq_term = 'Daily' and scheduled_date between last_transaction_date and last_working_day 
           AND datediff(last_working_day, Scheduled_Date) > 1 THEN datediff(last_working_day, Scheduled_Date)
           -- WHEN freq_term = 'Daily' AND datediff(last_working_day, Scheduled_Date) > 1 THEN datediff(last_working_day, Scheduled_Date) 

           -- when freq_term = 'Weekly' and scheduled_date between last_transaction_date and last_working_day 
           -- AND datediff(last_working_day, Scheduled_Date) > 7 THEN datediff(last_working_day, Scheduled_Date)
            WHEN freq_term = 'Weekly' AND datediff(last_working_day, Scheduled_Date) > 7 THEN datediff(last_working_day, Scheduled_Date)

           WHEN freq_term = 'Bi-Monthly' AND datediff(last_working_day, Scheduled_Date) > 14 THEN datediff(last_working_day, Scheduled_Date)
           WHEN freq_term = 'Monthly' AND datediff(last_working_day, Scheduled_Date) > 30 THEN datediff(last_working_day, Scheduled_Date) END 'DPD'
from
(
select id, 
      freq_term,
      max_date 'Last_Transaction_date',
      t3.date 'Scheduled_date',
      date(last_day(date) - (CASE DAYOFWEEK(last_day(date)) WHEN 1 THEN 2 WHEN 7 THEN 1 ELSE 0 END)) as 'Last_working_day'
from
  (
    select 
      jlp.id, 
      jlp.freq_term,
      t1.max_date,
      t1month,
      t1year
    from jos_lender_portfolio jlp
    inner join 
      (
        select lpid, year(date) t1year, month(date) t1month, max(date) max_date
        from jos_lender_transactions
        where description in('Payment', 'Partial Payoff', 'Early Payoff') 
        and date <= '2018-01-01'
        group by lpid, year(date),month(date)
      )t1 on jlp.id = t1.lpid
    where id = 1021
    order by 3
  )t
inner join 
  (SELECT 
      lpid, 
      date,
      MONTH(DATE) t3month,
      year(date) t3year  
   from jos_lender_trans_backup where description = 'Payment' and lpid = 1021 order by date
  )t3
on t.id = t3.lpid and t.t1month = t3.t3month and t.t1year = t3.t3year
)y
group by id, last_day(Last_Transaction_date)
order by Scheduled_Date;

根据MySQL 5.6

0 个答案: