如何计算向量的置信区间？

Question

我有一个矢量：

vector <- c(12, 17, 24, 35, 23, 34, 56)

如何在R？

中计算此向量的置信区间（90％，99％，95％）

这是我想要的结果示例： enter image description here

Answer 1

这是一个根据t分布计算置信区间的函数：

confidence_interval <- function(vector, interval) {
  # Standard deviation of sample
  vec_sd <- sd(vector)
  # Sample size
  n <- length(vector)
  # Mean of sample
  vec_mean <- mean(vector)
  # Error according to t distribution
  error <- qt((interval + 1)/2, df = n - 1) * vec_sd / sqrt(n)
  # Confidence interval as a vector
  result <- c("lower" = vec_mean - error, "upper" = vec_mean + error)
  return(result)
}

您提供的向量和间隔的示例用法：

> vector <- c(12, 17, 24, 35, 23, 34, 56)
> confidence_interval(vector, 0.90)
   lower    upper 
17.97255 39.45602 
> confidence_interval(vector, 0.95)
   lower    upper 
15.18797 42.24060 
> confidence_interval(vector, 0.99)
    lower     upper 
 8.219946 49.208626  

我this is the tutorial从中开发了这种方法。