Question

Here my socket.c as server simply listen on a port: the succinct code like below, I just want the code listening but not exit the process.

#include <stdio.h>
#include <stdlib.h>

#include <netdb.h>
#include <netinet/in.h>
#include <arpa/inet.h>

#include <string.h>

#define DEFAULT_PORT 27015

int main(int argc, char *argv[]) {

    int so = socket(0,1,0);

    struct sockaddr_in serv_addr, cli_addr;

    bzero(&serv_addr,sizeof(serv_addr));

    serv_addr.sin_family = AF_INET;
    serv_addr.sin_addr.s_addr = INADDR_ANY;
    serv_addr.sin_port = htons(DEFAULT_PORT);

    listen(so,5);

    accept(so,NULL,NULL);


    return 0;

}

absolutely some hard code in here. but when I gcc a.c compile it and run it. it will exit rather than listening.

So what's wrong with my code ????????????

Answer 1

You're not creating a stream socket over AF_INETthat's why its not listening to the socket.

The code for AF_INET is 2 and not 0.

change the code as

int so = socket(AF_INET, SOCK_STREAM, 0);

or

 int so = socket(2, 1, 0);

it will work

You also need to bind the port number on which the server will listen. Binding is not must for client port but is a must for Server port number

bind(so, (struct sockaddr *)&serv_addr, sizeof(serv_addr));

socket listen and accept in C programme language

1 个答案: