Question

我有几个列名，我需要从中获取中间字符串。例如;

从此列表中

"RHC3934__Bcell__.7DEA7B","RHC3944__Bcell__.7DEA7B",  "RHC3962__Tcell__.C6E879", "RHC4003__Bcell__.7DEA7B", "RHC4005__Bcell__.7DEA7B", "RHC4007__Bcell__.7DEA7B"

我需要为每个元素获得＆＃34; Bcell＆＃34; 。

任何帮助解决这个问题都表示赞赏。

Answer 1

试试这个：

library(stringr)
a <- c("RHC3934__Bcell__.7DEA7B","RHC3944__Bcell__.7DEA7B",  "RHC3962__Tcell__.C6E879", "RHC4003__Bcell__.7DEA7B", "RHC4005__Bcell__.7DEA7B", "RHC4007__Bcell__.7DEA7B")

result <- str_match(a, "__(.*?)__")[,2]

输出 -

> result
[1] "Bcell" "Bcell" "Tcell" "Bcell" "Bcell" "Bcell"

如果您特别想要 Bcell ，那么 -

final_res <- result[result=="Bcell"]

拆分矢量以获得中间值

1 个答案: