Question

我在下面有一个集合示例

//two dimensional array of spots
var spots = [[Spot]]();

//than you can store your spot arrays inside this two dimensional array
spots.append(spot2);

//accessing the spots via contentMode-Index (I would rename the contentMode to spotsIndex or something similar)
let currentSpots = spots[self.contentMode];

现在我想写一个mongodb查询，这个查询将返回isdeliver TRUE多于一个且具有相同的Order和Type 需要确切的输出

ROW Order Type   isdeliver
1     T      W       TRUE
2     T      L       TRUE
3     T      W       TRUE
4     T      L       FALSE
5     C      L       TRUE
6     C      L       TRUE
7     C      W       TRUE
6     C      W       FALSE

Answer 1

尝试使用此聚合按多个字段进行分组，此处我们按Order，Type和isdeliver进行分组，过滤所有数量少于两个

db.col.aggregate(
    [
        {$group : {
            _id : {$concat : ["$Order", "$Type", "$isdeliver"]}, 
            count : {$sum : 1},
            data : {$push : "$$ROOT"}
            }
        },
        {$match : {"count" :{ $gt : 1}}},
        {$unwind : "$data"},
        { $replaceRoot: { newRoot: "$data" } }

    ]
)

或

db.col.aggregate(
    [
        {$group : {
            _id : {
                Order : "$Order", Type : "$Type", isdeliver : "$isdeliver"
            }, 
            count : {$sum : 1},
            data : {$push : "$$ROOT"}
            }
        },
        {$match : {"count" :{ $gt : 1}}},
        {$unwind : "$data"},
        { $replaceRoot: { newRoot: "$data" } }

    ]
)

集合

> db.col.find()
{ "_id" : ObjectId("5a73500cd6c0ccee5268a15f"), "ROW" : 1, "Order" : "T", "Type" : "W", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a160"), "ROW" : 2, "Order" : "T", "Type" : "L", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a161"), "ROW" : 3, "Order" : "T", "Type" : "W", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a162"), "ROW" : 4, "Order" : "T", "Type" : "L", "isdeliver" : "FALSE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a163"), "ROW" : 5, "Order" : "C", "Type" : "L", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a164"), "ROW" : 6, "Order" : "C", "Type" : "L", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a165"), "ROW" : 7, "Order" : "C", "Type" : "W", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a166"), "ROW" : 6, "Order" : "C", "Type" : "W", "isdeliver" : "FALSE" }

结果

> db.col.aggregate( [ {$group : { _id : {$concat : ["$Order", "$Type", "$isdeliver"]},  count : {$sum : 1}, data : {$push : "$$ROOT"} } }, {$match : {"count" :{ $gt : 1}}}, {$unwind : "$data"}, { $replaceRoot: { newRoot: "$data" } }  ] )
{ "_id" : ObjectId("5a73500cd6c0ccee5268a15f"), "ROW" : 1, "Order" : "T", "Type" : "W", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a161"), "ROW" : 3, "Order" : "T", "Type" : "W", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a163"), "ROW" : 5, "Order" : "C", "Type" : "L", "isdeliver" : "TRUE" }
{ "_id" : ObjectId("5a73500cd6c0ccee5268a164"), "ROW" : 6, "Order" : "C", "Type" : "L", "isdeliver" : "TRUE" }
>

修改

在$group
之后按订单类型进行过滤
db.col.aggregate( [ {$group : { _id : { Order : "$Order", Type : "$Type", isdeliver : "$isdeliver" }, count : {$sum : 1}, data : {$push : "$$ROOT"} } }, {$match : {$and : [{"count" :{ $gt : 1}}, {"_id.Order" : {$eq : "T"}}]}}, {$unwind : "$data"}, { $replaceRoot: { newRoot: "$data" } } ] )

mongodb通过多个字段查找组

1 个答案: