Question

我正在使用翻译

写作

表1

id number type
1  6      111  
1  5      111
1  6      113
2  3      112
2  6      111

我需要按＆＃34;类型＆＃34;的值对组进行求和。和＆＃34; id＆＃34; 我希望看到的结果

结果表

id  type111 type112 typ113
1   11      0       6
2   6       3       0

Answer 1

尝试将SUM与CASE一起使用：

SELECT ID, 
SUM(CASE WHEN type = 111 THEN number END) AS type111,
SUM(CASE WHEN type = 112 THEN number END) AS type112,  
SUM(CASE WHEN type = 113 THEN number END) AS typE113,  
FROM TABLE1
GROUP BY ID

Answer 2

另一种使用pivoting的方式：

SELECT  id,
        ISNULL([111],0) as Type111, 
        ISNULL([112],0) as Type112, 
        ISNULL([113],0) as Type113
FROM (
        SELECT  id, 
                number, 
                [type]   
        FROM Table1
    ) AS SourceTable  
PIVOT (SUM(number) FOR [type] IN ([111], [112], [113]) 
) AS PivotTable;

输出：

id          Type111     Type112     Type113
----------- ----------- ----------- -----------
1           11          0           6
2           6           3           0

(2 rows affected)

如果各种类型都很高 - 使用动态SQL来构建和执行查询。

TSQL与类型的总和

2 个答案: