我见过两种类型的if / else，哪一种更快？
a==b ? cout<<"a" : cout<<"b";
OR
set('hola')==set('loha')
答案 0 :(得分：4)
三元条件是一种滥用，因为decltype(cout<<"a")是一种可用于三元条件的类型只是巧合：
cout << (a == b ? "a" : "b");
会比if else更容易理解，也可能比static <T> void diff(Iterator<T> lefts, Iterator<T> rights, Comparator<T> comparator,
Consumer<T> onlyLeft, Consumer<T> equals, Consumer<T> onlyRight) {
while (lefts.hasNext() && rights.hasNext()) {
recur(lefts.next(), rights.next(), lefts, rights, comparator, onlyLeft, equals, onlyRight);
}
if (!lefts.hasNext()) {
rights.forEachRemaining(onlyRight);
}
if (!rights.hasNext()) {
lefts.forEachRemaining(onlyLeft);
}
}
static <T> void recur(T left, T right, Iterator<T> lefts, Iterator<T> rights,
Comparator<T> comparator, Consumer<T> onlyLeft, Consumer<T> equals,
Consumer<T> onlyRight) {
if (comparator.compare(left, right) == 0) {
equals.accept(left);
} else if (comparator.compare(left, right) < 0) {
onlyLeft.accept(left);
if (lefts.hasNext()) {
recur(lefts.next(), right, lefts, rights, comparator, onlyLeft, equals, onlyRight);
} else {
onlyRight.accept(right);
}
} else {
onlyRight.accept(right);
if (rights.hasNext()) {
recur(left, rights.next(), lefts, rights, comparator, onlyLeft, equals, onlyRight);
} else {
onlyLeft.accept(left);
}
}
}
，public static void main(String[] args) {
List<String> tableOne = Lists.newArrayList("1", "2", "3", "4", "5", "6");
List<String> tableTwo = Lists.newArrayList("2", "2", "5", "7", "8");
diff(tableOne.iterator(), tableTwo.iterator(), String::compareTo,
left -> System.out.println("Left " + left),
both -> System.out.println("Both " + both),
right -> System.out.println("Right " + right));
}
更容易处理，否则你应该更清楚。
并相信您的编译器进行优化。如果您有任何疑问，请检查输出组件。
答案 1 :(得分：2)
对你的程序来说，任何一个的表现都不会是灾难性的。
这一切都取决于代码的可读性。
第三级运算符只有一个语句的限制，无论是真还是假。