Question

我有一个测试用例，我正在使用执行程序服务并调用许多可调用线程。这些线程可能导致成功调用或可能发出异常（这是预期的行为）。我需要断言未来的对象要么抛出异常，要么返回正确的响应。

for(Future<Resp> future : futureList) {
Assertions.assertThatThrownBy(() -> 
futureResponse.get()).isInstanceOf(ExecutionException.class);
// or
Assertions.assertThat(futureResponse.get()).isEqualTo(RespObj);
}

我如何断言这个＆＃34; OR＆＃34;行为？

Answer 1

您可以使用try catch阻止：

  for(Future<Resp> future : futureList) {
        try {
            Assertions.assertThat(futureResponse.get()).isEqualTo(RespObj);
        } catch (Throwable e) {
            Assertions.assertThat(e).isInstanceOf(ExecutionException.class);
        }
    }

Answer 2

如果是ExecutionException，您可能需要检查其原因。

    for (Future<Resp> future : futureList) {
        try {
            Resp got = future.get();
            assertValidResp(got); // check normal behavior (eg not null)
        }
        catch (ExecutionException e) {
            Throwable cause = e.getCause();
            assertAcceptedException(cause); // check for expected abnormal behavior (eg instanceof check)
        }
    }

AssertJ断言抛出异常或结果

2 个答案: