从阵列中过滤掉元素的最有效方法。红宝石

Question

说我有一个像这样的交易清单：

all = [{"timestamp"=>"2018-01-18T02:57:34.959Z", "toAddress"=>"Alice", "amount"=>"50"},
 {"timestamp"=>"2018-01-18T02:57:35.016Z", "fromAddress"=>"Alice", "toAddress"=>"Bob", "amount"=>"12.5"},
 {"timestamp"=>"2018-01-18T16:53:16.747Z", "toAddress"=>"50", "amount"=>"50"},
 {"timestamp"=>"2018-01-18T16:53:27.572Z", "fromAddress"=>"50", "toAddress"=>"alice", "amount"=>"50"},
 {"timestamp"=>"2018-01-18T16:53:38.853Z", "fromAddress"=>"alice", "toAddress"=>"Alice", "amount"=>"50"},
 {"timestamp"=>"2018-01-23T23:35:03.792Z", "fromAddress"=>"Alice", "toAddress"=>"alice", "amount"=>"10"},
 {"timestamp"=>"2018-01-23T23:35:25.464Z", "fromAddress"=>"Alice", "toAddress"=>"Bob", "amount"=>"1"},
 {"timestamp"=>"2018-01-23T23:35:48.835Z", "fromAddress"=>"Alice", "toAddress"=>"Bob", "amount"=>"1"},
 {"timestamp"=>"2018-01-23T23:47:46.485Z", "fromAddress"=>"Alice", "toAddress"=>"Bob", "amount"=>"1"},
 {"timestamp"=>"2018-01-23T23:48:31.953Z", "fromAddress"=>"Alice", "toAddress"=>"Bobz", "amount"=>"1"},
 {"timestamp"=>"2018-01-24T18:11:04.444Z", "fromAddress"=>"Alice", "toAddress"=>"Bobz", "amount"=>"1"},
 {"timestamp"=>"2018-01-24T18:28:40.680Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"3"},
 {"timestamp"=>"2018-01-24T18:36:53.179Z", "fromAddress"=>"Alice", "toAddress"=>"Sally", "amount"=>"3"},
 {"timestamp"=>"2018-01-24T18:39:14.926Z", "fromAddress"=>"Alice", "toAddress"=>"Sally", "amount"=>"3"},
 {"timestamp"=>"2018-01-24T18:39:40.937Z", "fromAddress"=>"Alice", "toAddress"=>"Sally", "amount"=>"3"},
 {"timestamp"=>"2018-01-24T18:40:11.686Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T18:40:13.720Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T18:41:32.832Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T18:49:10.052Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T18:49:11.729Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T18:50:09.862Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T19:14:46.326Z", "fromAddress"=>"Alice", "toAddress"=>"bob", "amount"=>"2"},
 {"timestamp"=>"2018-01-24T20:29:30.973Z", "fromAddress"=>"Alice", "toAddress"=>"Bob", "amount"=>"3"},

...

它继续用于页面。消除具有无效toAddress的交易的最快方法是这样的：

all.select do |t|
   t['toAddress'] != '50'
end

按toAddress对其进行分组然后过滤会有多糟糕？为什么好或坏？

我有这样的想法：

all.group_by do |t|
   t['toAddress']
end.select do |group, trans|
   group != '50'
end

从时间复杂的角度来看，一个人比另一个人差多少？