我正在尝试运行我认为简单的COUNT
查询,尽管我对COUNT
并不是很精通。
我正在跑步:
SELECT SourceID, COUNT(*) as SourceCount
FROM dbo.Capture
WHERE SourceID in (37, 38, 130, 131, 132, 133)
GROUP BY SourceID
此查询的结果仅显示SourceID
的COUNT大于零记录的行。如何让结果显示所有那些SourceID,包括没有计数的那些,我希望在SourceCount
列中看到零或NULL,并不重要。
感谢。
答案 0 :(得分:2)
SELECT val.id, COUNT(*) as SourceCount
FROM (values (37), (38), (130), (131), (132), (133)) val(id)
LEFT JOIN dbo.Capture
on SourceID = val.id
GROUP BY val.id
答案 1 :(得分:1)
试试这个:
SELECT SourceID, COUNT(*) AS SourceCount FROM dbo.Capture
WHERE SourceID IN (37, 38, 130, 131, 132, 133)
GROUP BY SourceID
UNION
SELECT *,0 FROM dbo.Split('137, 38, 130, 131, 132, 133',',')
WHERE item NOT IN (SELECT SourceID FROM dbo.Capture WHERE SourceID IN (37, 38, 130, 131, 132, 133))
以下是dbo.Split
函数的源代码:
CREATE FUNCTION [dbo].[Split] (@InputString VARCHAR(8000),@Delimiter VARCHAR(50))
RETURNS @Items TABLE (Item VARCHAR(8000))
AS
BEGIN
IF @Delimiter = ' '
BEGIN
SET @Delimiter = ','
SET @InputString = REPLACE(@InputString, ' ', @Delimiter)
END
IF (@Delimiter IS NULL OR @Delimiter = '')
SET @Delimiter = ','
DECLARE @Item VARCHAR(8000)
DECLARE @ItemList VARCHAR(8000)
DECLARE @DelimIndex INT
SET @ItemList = @InputString
SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
WHILE (@DelimIndex != 0)
BEGIN
SET @Item = SUBSTRING(@ItemList, 0, @DelimIndex)
INSERT INTO @Items VALUES (@Item)
SET @ItemList = SUBSTRING(@ItemList, @DelimIndex+1, LEN(@ItemList)-@DelimIndex)
SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
END -- End WHILE
IF @Item IS NOT NULL -- At least one delimiter was encountered in @InputString
BEGIN
SET @Item = @ItemList
INSERT INTO @Items VALUES (@Item)
END
-- No delimiters were encountered in @InputString, so just return @InputString
ELSE INSERT INTO @Items VALUES (@InputString)
RETURN
END -- End Function
答案 2 :(得分:0)
尝试子查询
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