这是我的剧本
SELECT COUNT( [Id]) as [Count Of Register],
Tag as [Tag]
FROM [Members]
Group By Tag
Order By [Count Of Register] Desc;
返回的表格如下:
Count Tag
550 ----1
550 ----2
545 ----3
545 ----4
545 ----5
所以,这次我需要Count of Tag,Group by这个新的Count字段。
某些返回值如:
2 ---550
3 ---545
有没有办法不使用新表或模板表或任何存储表只是通过查询?
答案 0 :(得分:15)
SELECT [Count Of Register], COUNT(1) [Grouped Count]
FROM
(
SELECT COUNT( [Id]) as [Count Of Register],
Tag as [Tag]
FROM [Members]
Group By Tag
) MyTable
GROUP BY [Count Of Register]
答案 1 :(得分:1)
您可以使用
SELECT [Count Of Register], COUNT(*) FROM
(SELECT COUNT([Id]) as [Count Of Register], Tag as [Tag]
FROM [Members] GROUP BY Tag) q
GROUP BY [Count Of Register]
答案 2 :(得分:0)
的MySQL> create table order1(counter int(3)not null auto_increment primary key, - > tag int(3)); 查询OK,0行受影响(0.01秒)
的MySQL>插入order1值(500,20); //按需要插入somany值并检查 插入order1值(500,20); 插入order1值(600,20); MySQL的>选择计数器,按计数器从order1组计数(*)