Question

我有一张包含交易，时间戳和用户的表格。

CREATE TABLE [dbo].[Transactions]
(
    [transaction_ts] [datetime] NULL,
    [user_id] [bigint] NULL,
    [transaction_id] [bigint] NULL,
    [item] [varchar](50) NULL
)

对于每个user_id，我需要选择他们在第一次交易和72小时后进行的所有交易。

--get first and last timestamps for range
DROP TABLE IF EXISTS #first;

SELECT mt.transaction_ts as first_trans,mt.user_id 
INTO #first
FROM Transactions mt 
INNER JOIN
    (SELECT user_id, MIN(transaction_ts) MinDate
     FROM Transactions
     GROUP BY user_id) t ON mt.user_id = t.user_id AND mt.transaction_ts = t.MinDate;

ALTER TABLE #first
ADD first_trans_plus_72 datetime;

UPDATE #first 
SET first_trans_plus_72 = DATEADD(hour, 72, first_trans)

--loop through user_id and select ranges using variables
DECLARE @Table TABLE (user_id bigint, Id int identity(1,1));

INSERT INTO @Table 
    SELECT DISTINCT user_id 
    FROM #first;

DECLARE @max int;
DECLARE @SQL VARCHAR(MAX);
DECLARE @user_id VARCHAR(max);
DECLARE @first VARCHAR(max);
DECLARE @first_trans_plus_72 VARCHAR(max);
DECLARE @id int = 1;

SELECT @max = MAX(Id) FROM@Table;

WHILE (@id <= @max)
BEGIN
    SELECT @user_id = user_id FROM @Table WHERE Id = @id
    SELECT @first = first_trans FROM #First WHERE user_id = @user_id
    SELECT @first_trans_plus_72 = first_trans_plus_72 FROM #First WHERE user_id = @user_id
    SET @SQL = 'select * from Transactions 
                where transaction_ts between ' + @first + ' and ' + @first_trans_plus_72 + ' 
                and user_id = ' + @user_id + ';'
    PRINT(@SQL)
    EXEC(@SQL)
    SET @id = @id +1
END

这会生成正确的逻辑sql，但是datetime变量是字符串，因此查询错误输出。我尝试将日期时间变量（@first和@first_trans_plus_72设置为datetime，但这会导致转换错误。

有更简单的方法吗？

Answer 1

为什么在使用简单查询时会使用循环？

select t.*
from (select t.*, min(transaction_ts) over (partition by user_id) as min_tts
      from transactions t
     ) t
where t.transaction_ts <= dateadd(hour, 72, min_tts);

通常，最好使用基于集合的操作编写代码。它更简单，表现更好，更好。

您可以将其合并到更新中，但我认为没有必要。以上选择交易。您可以使用group by user_id对它们进行汇总 - 例如计算它们或对值进行求和。

T-SQL日期范围在循环中使用动态变量

1 个答案: