Question

嘿女士们，先生们，

我对T-SQl很新，但我需要知道这是否可行。我的数据看起来像这样：

location_id,initial_date,final_date,asset_id,fixed_fee,uid
1,1/1/2005 0:00,11/3/2010 0:00,10025,21,22T0TG9UT 
1,1/1/2005 0:00,7/26/2010 0:00,10026,21,22T0TG8AC 
1,1/1/2005 0:00,7/26/2010 0:00,10027,21,22T0TG8AF 
1,1/1/2005 0:00,4/20/2011 0:00,10028,21,22T0TG8AI 
1,6/13/2011 0:00,12/31/2048 0:00,10028,12.5,38P0WGUV3 
1,4/20/2011 0:00,6/13/2011 0:00,10028,21,3770QEMG1 
1,4/20/2011 0:00,6/13/2011 0:00,10029,21,3770QEUYX 
1,6/13/2011 0:00,12/31/2048 0:00,10029,12.5,38P0WH6G4 
1,1/1/2005 0:00,4/20/2011 0:00,10029,21,22T0TG8AK 
1,1/1/2005 0:00,6/13/2011 0:00,10030,21,22T0TG8AM 
1,6/13/2011 0:00,12/31/2048 0:00,10030,12.5,38P0WHG30 
1,6/13/2011 0:00,12/31/2048 0:00,10031,12.5,38P0WHN50 
1,1/1/2005 0:00,6/13/2011 0:00,10031,21,22T0TG8AR 
1,1/1/2005 0:00,4/14/2014 0:00,10158,21,22T0TG8AW 
1,4/15/2014 0:00,12/31/2048 0:00,10158,12.5,41M0TAZNL 
1,4/15/2014 0:00,12/31/2048 0:00,10159,12.5,41M0TBXIS 
1,1/1/2005 0:00,4/14/2014 0:00,10159,21,22T0TG8B0 
1,1/1/2005 0:00,4/14/2014 0:00,10160,21,22T0TG8B2 
1,4/15/2014 0:00,12/31/2048 0:00,10160,12.5,41M0TCKZM 
1,4/15/2014 0:00,12/31/2048 0:00,10161,12.5,41M0TD5P7 
1,1/1/2005 0:00,4/14/2014 0:00,10161,21,22T0TG8BH 
1,1/1/2005 0:00,7/26/2010 0:00,10162,21,22T0TG8BJ 
1,1/1/2005 0:00,11/3/2010 0:00,10163,21,22T0TG8BL 
1,1/1/2005 0:00,7/26/2010 0:00,10164,21,22T0TG8BN 
1,12/13/2010 0:00,12/31/2048 0:00,10333,15,33L0OR1MH 
1,12/13/2010 0:00,12/31/2048 0:00,10334,15,33L0ORB5R 
1,1/1/2005 0:00,12/31/2048 0:00,10336,5,22T0TG8BQ 
1,1/1/2005 0:00,12/31/2048 0:00,10337,5,22T0TG8BR 
1,1/1/2005 0:00,12/31/2048 0:00,10338,5,22T0TG8BT 
1,1/1/2005 0:00,12/31/2048 0:00,10339,5,22T0TG8BV

我遇到的是，某些资产被移动或其费用结构发生变化。在那时他们被给予final_date（12/31/2048只是一个占位符结束日期），然后创建一个具有相同信息的新资产，但是新的初始日期，UID和final_date为12/31 / 2048。

日期不允许重叠，似乎造成了大量其他错误。如果费用结构在1月1日发生变化，则列出的下一个日期必须是1月2日。所以我需要使用一些T-SQL来检查每个日期范围与下一个日期范围，无论asset_id和location_id在多行中匹配。

对于这方面的任何建议或一般指导，我将不胜感激。救命啊！

Answer 1

是的，用SQL可以解决这样的问题！

首先，我提出了这个解决方案，这是相当直接的。它只是查看表中具有匹配记录（基于资产ID和位置ID）的所有记录，其中日期范围重叠，使用BETWEEN运算符检查可能的组合。

SELECT
    A.[uid],
    A.[location_id],
    A.[asset_id],
    A.[initial_date],
    A.[final_date],
    A.[fixed_fee]
FROM [tbl] A
WHERE   EXISTS
            (
                SELECT 
                    * 
                FROM [tbl] B
                WHERE   A.[location_id] = B.[location_id]
                    AND A.[asset_id] = B.[asset_id]
                    AND A.[uid] != B.[uid]
                    AND (
                            A.[initial_date] BETWEEN B.[initial_date] AND B.[final_date]
                         OR A.[final_date] BETWEEN B.[initial_date] AND B.[final_date]
                         OR B.[initial_date] BETWEEN A.[initial_date] AND A.[final_date]
                         OR B.[final_date] BETWEEN A.[initial_date] AND A.[final_date]
                        )
            )
ORDER BY 
    A.[location_id],
    A.[asset_id],
    A.[initial_date]

......但后来我觉得自己有点创意，也想出了这个。它给出了相同的结果，但是这个结果构建了一系列所有可能的日期，然后将其连接到数据以查找哪些资产+位置组合有多个条目，然后它返回它找到的所有记录。

WITH [cte_min_max] AS
    (
        SELECT
            MIN([initial_date]) [min_date],
            MAX([initial_date]) [max_date]
        FROM #tbl
    ),
[cte_recursion] AS
    (
        SELECT
            [min_date] [date],
            [max_date]
        FROM [cte_min_max]

        UNION ALL

        SELECT
            DATEADD(DAY, 1, [date]),
            [max_date]
        FROM [cte_recursion]
        WHERE   [date] <= [max_date]
    ),
[cte_duplicates] AS
    (
        SELECT
            A.[date],
            B.[location_id],
            B.[asset_id]
        FROM [cte_recursion] A
        INNER JOIN #tbl B
        ON      A.[date] BETWEEN B.[initial_date] AND B.[final_date]
        GROUP BY 
            A.[date],
            B.[location_id],
            B.[asset_id]
        HAVING COUNT(*) >= 2
    )
SELECT
    A.[uid],
    A.[location_id],
    A.[asset_id],
    A.[initial_date],
    A.[final_date],
    A.[fixed_fee]
FROM #tbl A
WHERE   EXISTS
            (
                SELECT 
                    * 
                FROM [cte_duplicates] B
                WHERE   A.[location_id] = B.[location_id]
                    AND A.[asset_id] = B.[asset_id]
                    AND B.[date] IN (A.[initial_date], A.[final_date])
            )
ORDER BY 
    A.[location_id],
    A.[asset_id],
    A.[initial_date]
OPTION (MAXRECURSION 0)

比较同一资产的日期范围（多行？）（T-SQL）

1 个答案: