Question

我正在开发一款内置功能的应用，可连接到Wi-Fi接入点。用户输入密码到他们想要连接的接入点后，执行以下代码。我的问题是，即使我的android设备成功连接到AP后，约2秒后，运行if语句。或者有时它无法连接，但else语句运行。我究竟做错了什么？有没有更简单的方法来完成我想要做的事情？

    final WifiManager wifiMgr = (WifiManager) getApplicationContext().getSystemService(Context.WIFI_SERVICE);

    new Handler().postDelayed(new Runnable() {
        @Override
        public void run() {
            if (wifiMgr.isWifiEnabled()) {
                WifiInfo wifiInfo = wifiMgr.getConnectionInfo();

                if (wifiInfo.getNetworkId() == -1) {
                    Log.v("rht", "Problems connecting. Try again.");
                    Toast.makeText(NetworkScanner.this, "Problems connecting. Try again.", Toast.LENGTH_LONG).show();
                }
                else {
                    Log.v("rht", "Successfully Connected.");
                }
            }
        }
    }, 4000);

Answer 1

你可以这样做..

final Handler handler = new Handler();
    handler.postDelayed(new Runnable() {
      @Override
      public void run() {
        //Do something after 200ms
      }
    }, 200);

此解决方案仅适用于UI线程。否则在普通线程上，你需要实现looper，这不是最好的版本..

了解更多信息you can visit this link

Answer 2

这是init Handler对象

 Handler mHandler = new Handler();
    mHandler.posttoDealy(run,1000*10) // 10 Sec

调用为您的任务运行线程

Runnable run = new Runnable() {
      @Override
      public void run() {

//this will run after ten Sec

//mHandler.posttoDealy(run,1000*10) // 10 Sec for again and again loop

      }
    })

删除处理程序

mHandler.removeCallback(run)

Answer 3

使用Supplicant状态确实具有魅力。出于某种原因＆＃34; wifiInfo.getNetworkId（）== -1＆＃34;给了我不可预知的结果。最终我发现了一种不同的方法来检查我的Android设备是否连接到网络。非常感谢Donal Rafferty和Armand。他们都为this SO question

做出了贡献

    final WifiManager wifiMgr = (WifiManager) getApplicationContext().getSystemService(Context.WIFI_SERVICE);

    final Handler handler = new Handler();
    handler.postDelayed(new Runnable() {

        @Override
        public void run() {
            if (wifiMgr.isWifiEnabled()) {

                SupplicantState supState;
                supState = wifiInfo.getSupplicantState();

                if(supState != SupplicantState.COMPLETED) {
                    Log.v("rht", "Problems connecting. Try again.");
                }
                else {
                    Log.v("rht", "Successfully Connected.");
                }
            }
        }
    }, 4000);

如何正确调用处理程序方法延迟？

3 个答案: