Question

如何以分钟为单位找出时差。

以下是时间格式t1和t2

 t1 =  01/24 14:50:0

 t2 = 1/24 14:52:01

差异是两分钟

如何实现这个

我尝试了以下代码但没有工作：

fmt = '%m/%d %H:%M:%S'
d1 = datetime.strptime('01/24 14:50:0', fmt)
d2 = datetime.strptime('1/24 14:52:01', fmt)
d1_ts = time.mktime(d1.timetuple())
d2_ts = time.mktime(d2.timetuple())
print (int(d1_ts-d2_ts) / 60)

Answer 1

我以这种方式尝试过：

from datetime import datetime

# print("Hello Python")

t1 =  "31/12/2015 10:33:26"
t2 = "01/01/2016 10:33:37"

newdate1 = datetime.strptime(t1, "%d/%m/%Y %H:%M:%S")
newdate2 = datetime.strptime(t2, "%d/%m/%Y %H:%M:%S")

thedifference = newdate2 - newdate1

print(thedifference)
# Result: 1 day, 0:00:11

确保在顶部

导入所需内容

Answer 2

试试这个。

    from datetime import datetime

    fmt = '%m/%d %H:%M:%S'
    d1 = datetime.strptime('01/24 14:50:0', fmt)
    d2 = datetime.strptime('1/24 14:52:01', fmt)

    time_diff_in_secs = abs((d1-d2).total_seconds())

    print( time_diff_in_secs/60 ) #returns float

    #for int use, print( int(time_diff_in_secs/60) )

如何在python中找到时差

2 个答案: