Question

我试图列出我的SD卡中可用的所有歌曲专辑。我做得很成功，但我遇到了一个小问题。例如，如果我是一张专辑＆＃34; ABC＆＃34;，其中包含10位艺术家。然后，当我查询专辑时，它会显示专辑＆＃34; ABC＆＃34; 10次基于艺术家。专辑＆＃34; ABC＆＃34;将显示10次，每张专辑＆＃34; ABC＆＃34;将包含特定艺术家的歌曲。

显示如下，

ABC\artistA

ABC\artistB ........等等

我想要的是它应该显示专辑＆＃34; ABC＆＃34;有一次当我打开它时，那张专辑中的所有歌曲都应该在那里。

代码：

    final Uri uri = MediaStore.Audio.Albums.EXTERNAL_CONTENT_URI;
    final String _id = MediaStore.Audio.Albums._ID;
    final String album_name = MediaStore.Audio.Albums.ALBUM;
    final String totSongs = MediaStore.Audio.Albums.NUMBER_OF_SONGS;
    final String artist_Name = MediaStore.Audio.Albums.ARTIST;

    final String[] columns = {  _id, album_name, totSongs,artist_Name };

    Cursor cursor = getActivity().getContentResolver().query(uri, columns, null, null, null);
    if (cursor != null) {
        if (cursor.moveToFirst()) {
            do {



                id = cursor.getLong(cursor.getColumnIndex(_id));
                String name = cursor.getString(cursor.getColumnIndex(album_name));
                Uri sArtworkUri = Uri.parse("content://media/external/audio/albumart");
                albumArtUri = ContentUris.withAppendedId(sArtworkUri, id).toString();
                totalSongs = cursor.getString(cursor.getColumnIndex(totSongs));
                ArtistName = cursor.getString(cursor.getColumnIndex(artist_Name));
                AlbumsModel s = new AlbumsModel(id, name, albumArtUri,totalSongs,ArtistName);
                AlbumsList.add(s);

            } while (cursor.moveToNext());
        }


        cursor.close();

Answer 1

您可以使用List：

，而不是使用Map

HashMap<String, AlbumModel> albums = new HashMap();


Cursor cursor = getActivity().getContentResolver().query(uri, columns, null, null, null);
if (cursor != null) {
    if (cursor.moveToFirst()) {
        do {
            id = cursor.getLong(cursor.getColumnIndex(_id));
            String name = cursor.getString(cursor.getColumnIndex(album_name));
            Uri sArtworkUri = Uri.parse("content://media/external/audio/albumart");
            albumArtUri = ContentUris.withAppendedId(sArtworkUri, id).toString();
            totalSongs = cursor.getString(cursor.getColumnIndex(totSongs));
            ArtistName = cursor.getString(cursor.getColumnIndex(artist_Name));

            AlbumsModel album = albums.get(id);
            if(album == null){
               album = new AlbumsModel(id, name, albumArtUri,totalSongs,ArtistName);
               albums.put(id, album);
               continue;
            }
            //update album music count
            album.setTotalMusic(album.getTotalMusic() + totSongs);
            albums.put(id, album);

        } while (cursor.moveToNext());
    }

    cursor.close();

Answer 2

这就是你可以显示Album / Artist与Album只出现一次的方式（假设光标按专辑排序）： -

    String previous_album = "";
    for (AlbumsModel am: AlbumsList) {
        if(am.getAlbumName().equals(previous_album)) {
            Log.d("ALBUMINFO","\t\t" + am.getArtistName());

        } else {
            Log.d("ALBUMINFO",am.getAlbumName() + "\t" + am.getArtistName());
        }
        previous_album = am.getAlbumName();
    }

这将遵循您的代码并将输出写入日志（显然您可以根据需要进行定制），例如： -

01-24 20:54:21.705 2125-2125/albums.so.so48422731albums D/ALBUMINFO: ABC    ArtistA
01-24 20:54:21.705 2125-2125/albums.so.so48422731albums D/ALBUMINFO:        ArtistB
01-24 20:54:21.705 2125-2125/albums.so.so48422731albums D/ALBUMINFO:        ArtistC

查询专辑显示重复

2 个答案: