Question

所以，我有一个名为teams的数据库，它目前看起来像这样：

team_id | leader_id | student_id
1       | 123456    | 1234
2       | 1234      | 123456, 1234567890
3       | 1234      | 123456
4       | 0         | 12345, 1234, 1234567890
5       | 0         |
6       | 0         |

我的students数据库看起来像这样

student_id | first_name | last_name
123456     | qwer       | qwer
0          | asd        | zxc
1234567890 | mmm        |nnn

用户输入leader_id，用户最多可输入7 student_id。问题是，如果用户输入1 student_id，一切正常，但当用户输入的数据超过1 student_id时，则不止一次存储数据。

示例：

如果用户输入1234作为leader_id，并输入123456和1234567890作为student_id，则应将数据存储在一行中，不要将数据分成2行。

另一件事是，在最后3行中，用户输入3 student_id，数据存储在1行中，但它增加了2行，student_id

我的PHP

<?php

    error_reporting(0);

    require '../../connect.php';

    $leader_id = $_POST['leader_id'];
    $student_id = array(
        $_POST['student_id_1'],
        $_POST['student_id_2'],
        $_POST['student_id_3'],
        $_POST['student_id_4'],
        $_POST['student_id_5'],
        $_POST['student_id_6']
    );

    $students_save = array();

    if(!empty($leader_id)) {

        foreach ($student_id as $id) {

            if(!empty($id)) {

                array_push($students_save, $id);

            }
        }

        foreach ($students_save as $save) {

            $check_id = mysqli_query($link, "SELECT student_id FROM students WHERE student_id = $save");

            if(mysqli_num_rows($check_id)>0) {

                $students_save = implode(", ", $students_save);

                $result = mysqli_query($link, "INSERT INTO teams (leader_id, student_id)
                    VALUES ('$leader_id', '$students_save');");

                    if($result) {

                        header("Location: ../../../admin.php?message=Success!");

                    } else {

                        header("Location: ../../../admin.php?message=Sorry we ran into an error");

                    }

            } else {

                header("Location: ../../../admin.php?message=A Student ID Doesn't Exist");

            }

        }

    } else if(empty($leader_id)){

        header("Location: ../../../admin.php?Please add you're input values");

    }

 ?>

Answer 1

在编辑问题时，

如果你的结果是$，那么你所需要的只是打破你的foreach循环 successl所以如果（$ result）其余的代码将保留，则添加break 相同的

请参阅以下代码

    <?php

foreach ($students_save as $save) {

            $check_id = mysqli_query($link, "SELECT student_id FROM students WHERE student_id = $save");

            if(mysqli_num_rows($check_id)>0) {

                $students_save = implode(", ", $students_save);

                $result = mysqli_query($link, "INSERT INTO teams (leader_id, student_id)
                    VALUES ('$leader_id', '$students_save');");

                    if($result) {

                        header("Location: ../../../admin.php?message=Success!");
                        break; // add break here, as if your condition      
                    } else {

                        header("Location: ../../../admin.php?message=Sorry we ran into an error");

                    }

            } else {

                header("Location: ../../../admin.php?message=A Student ID Doesn't Exist");

            }

        }

Answer 2

如果有帮助，请尝试以下代码，

<?php
error_reporting(0);
require '../../connect.php';

$leader_id = $_POST['leader_id'];
$student_id = array();
if(isset($_POST['student_id_1'])) $student_id[] = $_POST['student_id_1'];
if(isset($_POST['student_id_2'])) $student_id[] = $_POST['student_id_2'];
if(isset($_POST['student_id_3'])) $student_id[] = $_POST['student_id_3'];
if(isset($_POST['student_id_4'])) $student_id[] = $_POST['student_id_4'];
if(isset($_POST['student_id_5'])) $student_id[] = $_POST['student_id_5'];
if(isset($_POST['student_id_6'])) $student_id[] = $_POST['student_id_6'];

if(!empty($leader_id)) {
  $students_save = implode(", ", $student_id);
  $check_id = mysqli_query($link, "SELECT student_id FROM students WHERE student_id IN ($students_save)");
  if(mysqli_num_rows($check_id)>0) {
    //$student_ids = array();
    //while($row = $check_id->fetch_array(MYSQLI_ASSOC))  $student_ids[] = $row['student_id'];
    //$students_save = implode(", ", $student_ids);
    $result = mysqli_query($link, "INSERT INTO teams (leader_id, student_id) VALUES ('$leader_id', '$students_save');");
    if($result) {
        header("Location: ../../../admin.php?message=Success!");
    } else {
        header("Location: ../../../admin.php?message=Sorry we ran into an error");
    }
  } else {
    header("Location: ../../../admin.php?message=A Student ID Doesn't Exist");
  }
} else if(empty($leader_id)) {
  header("Location: ../../../admin.php?Please add you're input values");
}
?>

此代码可以为您提供帮助。

注意：我已对部分代码添加了评论。如果删除评论，则只会插入学生表中存在的student_id。

MySQL查询重复项

2 个答案: