我正在Laravel 5.5
中构建一个小应用程序,我使用Guzzle Http
来调用api url并获得响应,很少有api调用具有某些条件有标题作为生成的请求的授权。我试图将标题放在这样的地方:
public function post(Request $request)
{
try {
if ($request->url_method == 'get') {
$request = $this->client->get($request->url, [ 'headers' => [ 'access_token' => $request->headers->access_token]]);
}
else if ($request->url_method == 'post')
{ $request = $this->client->post($request->url, [$request->request_data]); }
else { return response()->json(['data' => 'Invalid Method'],500); }
$response = \GuzzleHttp\json_decode($request->getBody());
return response()->json(['data' => json_decode($response->d)], $request->getStatusCode());
}
catch (ClientException $e) {
return response()->json(['data' => 'Invalid Request.'], $request->getStatusCode());
}
}
但这给了我错误:
未定义的属性:Symfony \ Component \ HttpFoundation \ HeaderBag :: $ access_token
请查看截图:
同样在控制台中通过浏览器进行调用时,它也会出现同样的错误:
在此帮助我,谢谢。
答案 0 :(得分:7)
试试这段代码
use GuzzleHttp\Client as GuzzleClient;
..
..
..
$headers = [
'Content-Type' => 'application/json',
'AccessToken' => 'key',
'Authorization' => 'Bearer token',
];
$client = new GuzzleClient([
'headers' => $headers
]);
$body = '{
"key1" : '.$value1.',
"key2" : '.$value2.',
}';
$r = $client->request('POST', 'http://example.com/api/postCall', [
'body' => $body
]);
$response = $r->getBody()->getContents();
答案 1 :(得分:-2)
尝试在访问令牌之前在所有小案例中添加承载,如下所示 -
$access_token = 'bearer '.$request->headers->access_token