如何在HandlerInterceptorAdapter中添加HttpServletRequest标头?

时间:2016-10-12 18:04:36

标签: java spring http-headers interceptor

在我们切换环境时,我尝试在我的请求中添加一个Authorization标头作为临时解决方法。我试图在一个扩展HandlerInterceptorAdapter的拦截器中处理它。

我使用了MutableHttpServletRequest类here以便能够将标头添加到请求中,但它似乎没有任何方法可以在拦截器中实际修改返回的请求。有什么想法吗?

编辑:或者我必须在过滤器中执行此操作吗?

2 个答案:

答案 0 :(得分:0)

HttpServletRequest类型对象是只读的,您应该这样做:

->创建一个扩展HttpServletRequestWrapper的类(添加一些行为,装饰器模式)

final public class MutableHttpServletRequest extends HttpServletRequestWrapper {

    private final Map<String, String> customHeaders;

    public MutableHttpServletRequest(HttpServletRequest request){
        super(request);
        this.customHeaders = new HashMap<String, String>();
    }

    public void putHeader(String name, String value){
        this.customHeaders.put(name, value);
    }

    public String getHeader(String name) {
        String headerValue = customHeaders.get(name);

        if (headerValue != null){
            return headerValue;
        }
        return ((HttpServletRequest) getRequest()).getHeader(name);
    }

    public Enumeration<String> getHeaderNames() {
        Set<String> set = new HashSet<String>(customHeaders.keySet());

        @SuppressWarnings("unchecked")
        Enumeration<String> e = ((HttpServletRequest) getRequest()).getHeaderNames();
        while (e.hasMoreElements()) {
            String n = e.nextElement();
            set.add(n);
        }
        return Collections.enumeration(set);
    }
}

->创建您的过滤器类

public class CustomGatewayFilter implements Filter {

    @Override
    public void doFilter(ServletRequest request, ServletResponse response,
                         FilterChain chain) throws IOException, ServletException {
        HttpServletRequest req = (HttpServletRequest) request;
        MutableHttpServletRequest mutableRequest = new MutableHttpServletRequest(req);
        mutableRequest.putHeader("referer", "custom value");
        chain.doFilter(mutableRequest, response);
    }
}

->并在您的配置类中添加

 .and().addFilterAfter(new CustomGatewayFilter(), ConcurrentSessionFilter.class)

答案 1 :(得分:-3)

{{1}}