public static void Main()
{
TcpListener server=null;
try
{
Int32 port = 58000;
IPAddress localAddr = IPAddress.Parse("127.0.0.1");
// TcpListener server = new TcpListener(port);
server = new TcpListener(localAddr, port);
// Start listening for client requests.
server.Start();
// DO ALL YOUR WORK
}
catch(SocketException e)
{
Console.WriteLine(e.ToString());
}
finally
{
// Stop listening for new clients.
server.Stop();
}
}
我有这个csv文件,每个单元格中都有这些类型的字符串。我想在每个字符串中的4位前分隔文本。我还希望每个字符串中有4位数字。这是我到目前为止提出的代码。
post_title
B Project Kodou Ambitious 0101 Boys Meet Girl
B Project Kodou Ambitious 0102 Boys Meet Girl
B J and the Bear 0110 Lobo
B J and the Bear 0111 Crackers
B O R N To Style 0101 Homeless Boy To Rock Star Glam
B O R N To Style 0101 Homeless Boy To Rock Star Glam
在此代码中,它会迭代每个字符串中的4位数字,但仅适用于前2个单元格。我是php的新手。任何人都可以帮助我如何通过这些csv行从每个字符串中获取4位数。提前致谢
答案 0 :(得分:1)
如果你想要数字之前的文字,数字,然后在数组中的数字之后发短信。如下所示 -
<?php
$array = [];
if (($handle = fopen("e.csv", "r")) !== FALSE) {
$i = 0;
while (($data = fgetcsv($handle, 1000, " ")) !== FALSE) {
$result = array();
$index = 0;
foreach ($data as $key=>$number) {
if (is_numeric($number)) {
$index++;
$result[$index][] = $number;
$index++;
}
$result[$index][] = $number;
}
unset($result[2][0]);
$array[] = [implode(' ',$result[0]),implode(' ',$result[1]),implode(' ',$result[2])];
}
fclose($handle);
}
echo "<pre/>";print_r($array);
?>
我本地的输出结果: -
Array
(
[0] => Array
(
[0] => B Project Kodou Ambitious
[1] => 0101
[2] => Boys Meet Girl
)
[1] => Array
(
[0] => B Project Kodou Ambitious
[1] => 0102
[2] => Boys Meet Girl
)
[2] => Array
(
[0] => B J and the Bear
[1] => 0110
[2] => Lobo
)
[3] => Array
(
[0] => B J and the Bear
[1] => 0111
[2] => Crackers
)
[4] => Array
(
[0] => B O R N To Style
[1] => 0101
[2] => Homeless Boy To Rock Star Glam
)
[5] => Array
(
[0] => B O R N To Style
[1] => 0101
[2] => Homeless Boy To Rock Star Glam
)
这就是我的CSV看起来: -