Question

我有以下数据框：

       location asset_status count   row
      <chr>          <chr>  <dbl>  <int>
 1  location1        Owned     1     1
 2  location1    Available     1     2
 3  location1        Owned     1     3
 4  location2        Owned     1     4
 5  location2        Owned     1     5
 6  location2        Owned     1     6
 7  location2        Owned     1     7
 8  location2    no status     1     8
 9  location3        Owned     1     9
10  location3        Owned     1    10

当我尝试使用此传播时，我收到以下错误：

df <- head(us_can_laptops,10) %>% 
  select(location,asset_status,count) %>% 
  #mutate(row = row_number()) %>% #excluded
  group_by(location) %>% 
  spread(asset_status,count)

Error: Duplicate identifiers for rows (4, 5, 6, 7), (1, 3)

因此，根据SO上与此相关的其他问题，我添加了一个带mutate的唯一标识符：

df <- head(us_can_laptops,10) %>% 
  select(location,asset_status,count) %>% 
  mutate(row = row_number()) %>%
  group_by(location) %>% 
  spread(asset_status,count)

但是这会返回：

    location     row   Available   `no status` Owned
 *        <chr> <int>     <dbl>       <dbl> <dbl>
 1  location2     4        NA          NA     1
 2  location2     5        NA          NA     1
 3  location2     6        NA          NA     1
 4  location2     7        NA          NA     1
 5  location2     8        NA           1    NA
 6  location3    10        NA          NA     1
 7  location3     9        NA          NA     1
 8  location1     1        NA          NA     1
 9  location1     2         1          NA    NA
10  location1     3        NA          NA     1

另外，每当我尝试总结电话时，它都会破坏我的传播。

这是期望的结果：

 location        Available   `no status` Owned
 *      <chr>     <dbl>       <dbl>      <dbl>
 1  location1        1          NA        2
 2  location2       NA          1         4
 3  location3       NA          NA        2

任何帮助将不胜感激。我知道这看起来像是重复的，但以下相关问题的答案仍然无法解决我的问题： Spread function Error: Duplicate identifiers for rows [duplicate] Spread with duplicate identifiers for rows 1

我在使用dplyr而非dcast

时真的在寻找解决方案

Answer 1

以下内容应该有效（至少提供所需的输出）：

df <- structure(list(location = c("location1", "location1", "location1", 
                                  "location2", "location2", "location2", "location2", "location2", 
                                  "location3", "location3"), asset_status = c("Owned", "Available", 
                                                                              "Owned", "Owned", "Owned", "Owned", "Owned", "no status", "Owned", 
                                                                              "Owned"), count = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), 
                     row = 1:10), row.names = c(NA, -10L), .Names = c("location", 
                                                                      "asset_status", "count", "row"), class = "data.frame")

library(dplyr)
library(tidyr)
df %>% 
  group_by(location, asset_status) %>% 
  summarise(count = sum(count)) %>% 
  spread(key = asset_status, value = count)

即使包含唯一行，Spread也会返回重复的标识符错误

1 个答案: