Question

我有一系列玩家，每个玩家都有很多分数。

我可以使用自定义的usort函数按照点的顺序轻松地对数组进行排序。

但是当两个玩家拥有相同数量的积分时，我需要将它们排在列表中的相同获胜位置。

E.g。

尼克 - 25
汤姆 - 18
Chris - 18
戴夫 - 16
James - 8

在这种情况下，我需要的数据是

Nick - 1st
汤姆 - （联合）第二
克里斯 - （联合）第二
Dave 3rd
James 4th

所以得分相等的球员被指定为相同的排名位置。

计算这些职位的最佳方法是什么？

谢谢！

Answer 1

我认为以下代码可以按要求完成工作：

$scores = array('Nick'=>25,'Tom'=>18,'Chris'=>18,'Dave'=>16, 'James'=> 8,);

$scores_numbers = array_unique(array_values($scores)); 
$scores_counter = array_count_values($scores);
$pos = 1;
foreach($scores_numbers as $num) {
    foreach($scores as $name=>$score) {
      if($num == $score) {
        if($scores_counter[$score] > 1) {
          echo  "$name - (joint) $pos<br />";
        } else {
          echo  "$name - $pos<br />";
        }
      }
    }
  $pos++;
}

我已更新代码以避免重复输出。

Answer 2

如果您要从数据库中检索玩家统计数据，那么下面的代码可用于对它们进行排名：

<?php

$players = [
    ['name' => 'Ash',
    'point' => 0
    ],
    ['name' => 'Bob',
     'point' => 10
    ],
    ['name' => 'Cane',
    'point' => 0
    ],
    ['name' => 'Dory',
    'point' => 6
    ],
    ['name' => 'Efat',
    'point' => 6
    ],
  ];

usort($players, function($v1, $v2){
    return $v2['point'] - $v1['point'];
});

$ranking = [];

$currentPosition = 0;
$heighestPoint = PHP_INT_MIN;

foreach($players as $player){
    if($heighestPoint !== $player['point']){
        $currentPosition++;
        $heighestPoint = $player['point'];
    }

        $ranking[$currentPosition][] = $player;
}

print_r($ranking);

输出：

Array
(
[1] => Array
    (
        [0] => Array
            (
                [name] => Bob
                [point] => 10
            )

    )

[2] => Array
    (
        [0] => Array
            (
                [name] => Dory
                [point] => 6
            )

        [1] => Array
            (
                [name] => Efat
                [point] => 6
            )

    )

[3] => Array
    (
        [0] => Array
            (
                [name] => Ash
                [point] => 0
            )

        [1] => Array
            (
                [name] => Cane
                [point] => 0
            )

    )

 )

Answer 3

这将通过额外修复为您提供所需内容：如果您在第2位有两名玩家，则下一位玩家应该在第4位。如果您不希望这个额外的修补程序移动$count++; if语句。

$count = 0;
$position = 0;
$last_score = -1;

foreach ($players as $player)
{
    $count++;

    if ($last_score !== $player->score)
    {
        $position = $count;
    }

    $player->position = $position;
    $last_score = $player->score;
}

Answer 4

愿它有所帮助

/*Below array must be sorted  */
$a1=array("Nick"=>25,"Tom"=>18,"Chris"=>18,"Dave"=>16,"James"=>8); 

$makeUnique=array_unique($a1);
$makeUnique=array_values($makeUnique);

$pArr=array_map('setPosition',$a1);

print_r($pArr);


function setPosition($a){
    Global $makeUnique;
    return array_search($a,$makeUnique)+1;
}

OUT PUT

数组（[Nick] =＆gt; 1 [Tom] =＆gt; 2 [Chris] =＆gt; 2 [Dave] =＆gt; 3 [James] =＆gt; 4）

Answer 5

我使用usort对关联数组

进行排序

$players = [["name" => "Nick" , "score" => 25] , ["name" => "Tom" , "score" => 18] , ["name" => "chris" , "score" => 18] , ["name" => "dave" , "score" => 16 ] , ["name" => "james" , "score" => 8]];

usort($players , function($a , $b) {return $b["score"] - $a["score"];} );

var_dump($players);

$lastScore = null;
$pos = 1;
foreach($players as $player)
{
    if($lastScore != null && $lastScore == $player["score"])
        echo $pos-1 . " - " . $player["name"] . '<br/>';
    else
        echo $pos++ . " - " . $player["name"] . '<br/>';

    $lastScore = $player["score"];
}

在teh playground

中查看此代码

PHP排序数组关节位置

5 个答案: